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Archy [21]
3 years ago
11

What is the equation of the following line written in general form? (The y-intercept is -1.)

Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

2x-y-1=0

Step-by-step explanation:

.

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A towns population is 43,425. About 125 people move out of the town each month. Each month, 200 people on average move into town
jolli1 [7]

Answer 1) x = 7 so in 7 months

2) 43,425 + 75x = 45,000 - 150x

Step-by-step explanation:

basically town A is gaining 75 people monthly and town B is decreasing 150 monthly so 43,425 + 75x = 45,000 - 150x and then you find out in 7 months both town will have equal population hope i helped

5 0
4 years ago
Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a downward sloped line crossing the y
anastassius [24]
Answer: The right hand limit is 4

-------------------------------

Start on the right side of the value x = 2. In other words, start at some value larger than 2, say x = 4. Starting at x = 4, move closer to x = 2. Move as close as you can. The closer x gets to 2, the closer y gets to 4. You'll never actually get to x = 2 or y = 4 because of the hole. However, the right-hand limiting value is 4 assuming you can keep getting closer and closer. 

Note: if you approach x = 2 from the left side, you arrive at a different y value So this suggests that overall, the limit at x = 2 doesn't exist. But the right hand limit (RHL) does exist as described above.
7 0
4 years ago
A radioactive substance decays according to the equation y=30( .88 )^x, where y is measured in grams of the radioactive substanc
Gelneren [198K]
The answer is: 4 idk.
7 0
3 years ago
Please help from 3 -5
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3 years ago
Find a solution of the quadratic equation.6x squared + 7x + 2 =0
worty [1.4K]

Given the equation:

6x^2+7x+2=0

We will use the following rule to find the solution to the equation:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

From the given equation: a = 6, b = 7, c = 2

So,

\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}

So, the answer will be option B) x = -1/2, -2/3

5 0
1 year ago
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