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kotykmax [81]
2 years ago
5

Solve

Mathematics
2 answers:
goblinko [34]2 years ago
8 0
The answer should be B
Alla [95]2 years ago
3 0

Answer:

B 390.000

Step-by-step explanation:

39. >>>move the decimal 4 places to the right, so essentially you're just adding 4 zeros to the 39 to get 390,000

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A grocery store so the six pack of bottled water for $3.79 a 12 pack for $6.89 which package cost The least per bottle explain y
il63 [147K]
Easiest way to find out the answer to this is to find out the price of every water bottle. To do that you have to divide the whole value by the amount of water bottles. (3.79/6 & 6.89/12) The first one should equal something around .63 each and the second should be around .57. Technically the second pack is cheaper than the other by around .6 cents.
4 0
3 years ago
Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be
Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of t=0.6482

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

h(t)=-16t^2 +v_{o}t+s       Eqn(1).

Where:

h(t) : is the height range as a function of time

v_{o}   : is the initial velocity

s     : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

h(t)=-16t^2 + v_{o}t + 40        Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that v_{o}=60ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+60t+40        Eqn.(3)

<u>Josh:</u>

We know that v_{o}=48ft/s

Thus Eqn. (2) becomes:

h(t)=-16t^2+48t+40       Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em>h(t)=0<em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

h(t)=0-16t^2+60t+40=0

Using the quadratic expression to find the roots of the quadratic we have:

t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec

Since time can only be positive we reject the t_{2} solution and we keep that Ben's book took t=4.3276 seconds to reach the ground.

Similarly solving for Josh we obtain

t_{1}=3.6794sec\\t_{2}=-0.6794sec

Thus again we reject the negative and keep the positive solution, so Josh's book took t=3.6794 seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

  • Josh's textbook reached the ground first
  • Josh's textbook reached the ground first by a difference of t=0.6482

3 0
3 years ago
Is negative 2 n 13/16 greater, or less than or equal to negative 2 11/14???
Kazeer [188]
-2 \frac{13}{16} \ \textless \  -2\frac{11}{14}
8 0
3 years ago
Jillian walked 0.5 miles before she started jogging at an average pace of 5 miles per hour. The equation d = 0.5 + 5t can be use
viktelen [127]
For this case we have the following equation:
 d = 0.5 + 5t
 We will describe the equation step by step.
 0.5: Initial distance Jillian walked
 5: speed with which Jillian begins to jog
 t: independent variable that indicates the number of hours
 y: dependent variable that indicates the distance traveled in miles
 Answer:
 
The variable variable is time and the dependent variable is distance.
3 0
3 years ago
Read 2 more answers
a contractor is on top of 167 ft Tower looking down at a 37 degree angle of depression at a package attached to a rope on the gr
ArbitrLikvidat [17]

Using trigonometry ratio

\sin 37^0=\frac{167}{x}\begin{gathered} 0.6018\text{ = }\frac{167}{x} \\ 0.6018x\text{ = 167} \\ x\text{ = }\frac{167}{0.6018}\text{ = 277.5ft} \end{gathered}

x = 277.5 ft

3 0
1 year ago
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