All categories

3 years ago

400 is ten times as much as

Mathematics

1 answer:

Mrrafil [7]3 years ago

3 0

40
Try dividing 400 by ten you'll get 40 (or just remove a zero or decimal point to the left when dividing by 10)

You might be interested in

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

Write an equation for the line parallel to the line 5/8x−7/6y =2 through the point (7,−1).

LiRa [457]

$y = - \frac{28}{48x - 15} - \frac{125}{321}$ is the answer.

Step-by-step explanation:

For this question,

• First, find the slope of the line parallel to the line 5/8x−7/6y=2 :-

$m = - \frac{28}{ - 15 + 48x}$

•Second, find the equation of the line,

$y = - \frac{28}{48x - 15} - \frac{125}{321}$

7 0

2 years ago

Write three hundred twenty-eight, four hundred seven in expanded form.

aleksandrvk [35]

I think the answer is 300+20+8
and 400+7 :)

8 0

3 years ago

Read 2 more answers

1) Si se extrae una carta de un paquete de 52 cartas de las cuales 26 son negras (13 espadas A, 2, 3, … , 10, J, Q, K); 13 son t

Daniel [21]

1) If a card is drawn from a pack of 52 cards of which 26 are black (13 spades A, 2, 3,…, 10, J, Q, K); 13 are clovers); and 26 are red (13 hearts and 13 diamonds), find the probability of:

a) that the letter is a K.

b) that the card is red.

c) That the card is diamond.
Help them

5 0

3 years ago

Use p = 2 and p = 8 to determine if the two expressions are equivalent. 4(2 + p) 14 + p Complete the statements. If both

Aleks [24]

Answer:

p=2 1st is 16 p=8 second is 22 they arent equivalent

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers