The probability of a hand of 13 cards contains all 4 of one of the denominations, say Aces, is given by:
The same probability applies to getting all 4 of each of the other denominations.
Therefore the required probability is:
The answer is 0.0343.
Answer: Choice A
g(x) = sqrt(2x)
====================================================
Explanation:
"sqrt(x)" is shorthand for "square root of x"
f(x) = 3x^2 is given
g( f(x) ) = x*sqrt(6) is also given
One way to find the answer is through trial and error. This would only apply of course if we're given a list of multiple choice answers.
------------------
Let's start with choice A
g(x) = sqrt(2x)
g( f(x) ) = sqrt(2 * f(x) ) .... replace every x with f(x)
g( f(x) ) = sqrt(2 * 3x^2 ) .... plug in f(x) = 3x^2
g( f(x) ) = sqrt(6x^2 )
g( f(x) ) = sqrt(x^2 * 6)
g( f(x) ) = sqrt(x^2)*sqrt(6)
g( f(x) ) = x*sqrt(6)
We found the answer on the first try. So we don't need to check the others.
------------------
But let's try choice B to see one where it doesn't work out
g(x) = sqrt(x + 3)
g( f(x) ) = sqrt( f(x) + 3)
g( f(x) ) = sqrt(3x^2 + 3)
and we can't go any further other than maybe to factor 3x^2+3 into 3(x^2+1), but that doesn't help things much to be able to break up the root into anything useful. We can graph y = x*sqrt(6) and y = sqrt(3x^2 + 3) to see they are two different curves, so there's no way they are equivalent expressions.
44/4 = 11, so 11 small cabs would be needed to transport 44 people.
Answer:
621
Step-by-step explanation:
23(39-12) > 23(27)
23(27)= 621
Area of square = Side × side
= 1 6/7 × 1 6/7
= 3.45 square millimeters
