I would go C because that way it gets her prepared to answer any techie questions they would have for her and would make her a better option.
// making the class
class Counter {
int counter;
int limit;
// Constructor
Counter(int a, int b){
counter = a;
limit = b;
}
// static function to increment
static increment(){
if(counter<limit)
nCounter+=1;
}
// Decrement function
void decrement(){
if(counter>0)
nCounter-=1;
}
int getValue(){
return counter;
}
static int nCounter;
int getNCounters(){
return nCounter;
}
};
// Initializa the static
int Counter::nCounter = 0;
Answer:
A is your answer hope this helps
Answer:
The correct answer is C.
Explanation:
You have to do 0xFF20 - 0x1037 but first, you need to convert the counts from hexadecimal base system to decimal base system using this formula:
, where position of the x₀ is the rightmost digit of the number.
<em>Note: </em>
- A = 10.
- B = 11.
- C = 12.
- D = 13.
- E = 14.
- F = 15.
0xFF20 = 15*16³+15*16²+2*16¹ = 65312
0x1037 = 1*16³+3*16¹+7*16⁰ = 4151
Result: 65312 - 4151 = 61161