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2 years ago

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A rabbit is hopping along at an approximately constant speed of 3.9 m/s. The rabbit passes a crouched cat ready to chase the rab

bit. The cat takes off the instant the rabbit passes the cat, accelerating at 0.5 m/s2. How long does it take the cat to catch the rabbit

1 answer:

Firlakuza [10]2 years ago

4 0

Answer:

t = 7,8 s

Explanation:

From the instant, the rabbit passes the cat. The cat star running acceleration of 0,5 m/s² .

When the cat arrives at the speed of 3,9 m/s the cat catches the rabbit

Then for the cat arrives at 3,9 m/s nedds

v = vo + a*t vo = 0 then v = a*t

3,9 ( m/s) = 0,5 ( m/s² ) * t

t = 7,8 s

v = 3,9 m/s =

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