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Korolek [52]
3 years ago
14

according to newton's second law of motion of the net force acting on the object increases while the mass of the object remains

constant, what happens to the acceleration?
Physics
1 answer:
Licemer1 [7]3 years ago
4 0

Answer:

The Acceleration will increase

Explanation:

Newton's Second Law of motion: It states that the rate of change of momentum is directly proportional to the applied force and takes places along the direction of the force.

It can be expressed mathematically as,

F ∝ m(v-u)/t

Where (v-u)/t = a

F  = kma.

F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.

Therefore,

F = ma.

From the equation above,

If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.

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All circuits include
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A 50-kg block is at rest on a 15o slope. A force of 250 N is acting on the block up the slope parallel to it. If the block does
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The minimum value of the coefficient of static friction between the block and the slope is 0.53.

<h3>Minimum coefficient of static friction</h3>

Apply Newton's second law of motion;

F - μFs = 0

μFs = F

where;

  • μ is coefficient of static friction
  • Fs is frictional force
  • F is applied force

μ = F/Fs

μ = F/(mgcosθ)

μ = (250)/(50 x 9.8 x cos15)

μ = 0.53

Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.

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6 0
2 years ago
A drop
exis [7]

Answer:

27.5\  m

Explanation:

As we know that volume of cylinder is

v=\pi r^{2} *h

Where v=volume , h= height or thickness and r= radius

Here,

v= 10 m ,\  diameter= 10, \ r=\frac{diameter}{2} \ r=\frac{10}{2}\\ r=5

Putting these values in the previous equation , we get

10\ = \frac{22}{7} *5 *5*h\\ 14\ =\ 110*h\\h=\frac{110}{14} \\h=\frac{55}{2} \\\\h=27.5\  m

Therefore thickness is 27.5 m

7 0
3 years ago
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