All categories

3 years ago

The resistance of a conductor depends on all of the following, except _____.

2 answers:

5 0

Hello There!

The resistance of a conductor depends on all of the following except mass.
Mass wouldn't affect the resistance in any way.

Hope This Helps You!
Good Luck :)

- Hannah ❤

LekaFEV [45]3 years ago

5 0

The answer would be mass

You might be interested in

What goes through evaporation

Olegator [25]

Water goes through evaporation.

6 0

3 years ago

Read 2 more answers

If it takes Ashley 6.1 seconds to run at an average speed of 5.7 meters per second, what is the distance (in meters) she covers

Softa [21]

Answer:

34.8m

Explanation:

distance = speed x time

6.1 x 5.7 = 34.77

34.8

3 0

3 years ago

Why one part of the earth's surface is arid and dry and a nearby part is lush and wet is explained by the term?

Darina [25.2K]

The process that explains why one part of the earth's surface is arid and dry and a nearby part is lush and wet is areal differentiation. It is<span> an approach to geography that shows </span>the dependence of the distribution of physical and human phenomena and the relation to each other from the physical location. Areal integration on the other hand is the approach that studies how places interact with each other.

8 0

3 years ago

What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes th

max2010maxim [7]

Answer:

its D

Explanation:

edg2020

7 0

3 years ago

Read 2 more answers

In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The co

labwork [276]

Answer:

The answer is given below

Explanation:

u is the initial velocity, v is the final velocity. Given that:

$m_1=0.6kg,u_1=-5m/s(moving \ west),m_2=0.8kg,u_2=2m/s,k=1200N/m$

The final velocity of cart 1 after collision is given as:

$v_1=(\frac{m_1-m_2}{m_1+m_2})u_1+\frac{2m_2}{m_1+m_2}u_2\\ Substituting:\\v_1=\frac{0.6-0.8}{0.6+0.8} (-5)+\frac{2*0.8}{0.6+0.8}(2)= 5/7+16/7=3\ m/s$

The final velocity of cart 2 after collision is given as:

$v_2=(\frac{m_2-m_1}{m_1+m_2})u_2+\frac{2m_1}{m_1+m_2}u_1\\ Substituting:\\v_1=\frac{0.8-0.6}{0.6+0.8} (2)+\frac{2*0.6}{0.6+0.8}(-5)= 2/7-30/7=-4\ m/s$

b) Using the law of conservation of energy:

$\frac{1}{2}m_1u_1+ \frac{1}{2}m_2u_2=\frac{1}{2}m_1v_1+\frac{1}{2}m_2v_2+\frac{1}{2}kx^2\\x=\sqrt{\frac{m_1u_1+m_2u_2-m_1v_1-m_2v_2}{k}}\\ Substituting\ gives:\\x=\sqrt{\frac{0.6*(-5)^2+0.8*2^2-(0.6*3^2)-(0.8*(-4)^2)}{1200}}=\sqrt{0}=0\ cm$

7 0

3 years ago