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r-ruslan [8.4K]
3 years ago
6

FIND THE WEIGHT OF A 80 KG MAN ON THE SURFACE OF MOON? WHAT SHOULD BE HISS MASS ON THE EARTH AND ON THE MOON? (ge = 9.8 m/s2 ; g

m = 1.63 m/s2)
pls answer fast
Physics
1 answer:
elena55 [62]3 years ago
8 0

Weight = (mass) x (acceleration of gravity at the place where the mass is) .

Man's mass = 80 kg

His weight on Earth = (80 kg) x (9.8 m/s²) = 784 newtons (about 176 pounds)

His weight on the Moon = (80 kg) x (1.63 m/s²) = <em>130.4 newtons</em> (about  29.2 pounds)

His mass is <em>80 kg</em>.  Mass is the thing about him that doesn't change. 
He has the same mass on the Earth, on the Moon, or anywhere.

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A group of cells working together make up a(n)
Neko [114]
Answer: Tissue.

Molecules make up cells, cells make up tissue, tissue makes up organs, organs make up organ systems. 
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2 years ago
During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.146 kg baseball crashing through the pane
Nonamiya [84]

Answer:

Impulse, |J| = 0.6716 kg-m/s

Force, F = 63.35 N

Explanation:

It is given that,

Mass of the baseball, m = 0.146 kg

Initial speed of the ball, u = 15.3 m/s

Final speed of the ball, v = 10.7 m/s

To find,

(a) The magnitude of this impulse.

(b) The magnitude of the average force of the glass on the ball.

Solution,

(a) Impulse of an object is equal to the change in its momentum. It is given by :

J=m(v-u)

J=0.146\ kg(10.7-15.3)\ m/s

J = -0.6716 kg-m/s

or

|J| = 0.6716 kg-m/s

(b) Another definition of impulse is given by the product of force and time of contact.

t = 0.0106 s

J=F\times \Delta t

F=\dfrac{J}{\Delta t}

F=\dfrac{0.6716\ kg-m/s}{0.0106\ s}

F = 63.35 N

Hence, this is the required solution.

6 0
2 years ago
Submarine a travels horizontally at 11.0 m/s through ocean water. it emits a sonar signal of frequency f 5 5.27 3 103 hz in the
xeze [42]
Velocity of submarine A is vs = 11.0m/s
frequency emitted by submarine A. F = 55.273 × 10∧3HZ
Velocity of submarine B = vO = 3.00m/s
The given equation is
f' = ((V + vO) ((v - vS)) × f
The observer on submarine detects the frequency f'.
The sign of vO should be positive as the observer of submarine B is moving away from the source of submarine A.
The speed of the sound used in seawater is 1533m/s
The frequency which is detected by submarine B is 
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= 53.273 × 10∧3hz) ((1533 m/s - 4.5 m/s)/ (1533 m/s +11 m/s)
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Eduardwww [97]

Answer: find the answer in the explanation as kinetic energy converts to potential energy.

Explanation:

Before the truck driver sees a dog running into the road, The mechanical energy state of the truck will be kinetic energy at maximum.

Immediately he applied the brakes, the mechanical energy of the truck will be combination of kinetic energy and potential energy.

The kinetic energy will gradually decrease as potential energy continue to increase till it reaches maximum potential energy.

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3 0
3 years ago
Nearly all conventional piston engines have flywheels on them to smooth out engine vibrations caused by the thrust of individual
Artyom0805 [142]

Answer:

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Explanation:

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