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3 years ago

50 Points Help will give brainliest

Mathematics

1 answer:

gregori [183]3 years ago

4 0

1. To transform from standard form to vertex form you need to complete the square.

To transform from vertex form to standard form multiply the equation out and combine all the like terms.

2. The attributes from vertex form would be the roots ( zeros)

From standard form the attribute would be the lowest point, also known as the vertex.

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Answer:

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Step-by-step explanation:

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5. Find the general solution to y'''-y''+4y'-4y = 0

CaHeK987 [17]

For any equation,

$a_ny^(n)+\dots+a_1y'+a_0y=0$

assume solution of a form, $e^{yt}$

Which leads to,

$(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0$

Simplify to,

$e^{yt}(y^3-y^2+4y-4)=0$

Then find solutions,

$\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}$

For non repeated real root y, we have a form of,

$y_1=c_1e^t$

Following up,

For two non repeated complex roots $y_2\neq y_3$ where,

$y_2=a+bi$

and,

$y_3=a-bi$

the general solution has a form of,

$y=e^{at}(c_2\cos(bt)+c_3\sin(bt))$

Or in this case,

$y=e^0(c_2\cos(2t)+c_3\sin(2t))$

Now we just refine and get,

$\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}$

Hope this helps.

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Answer: wym and need more info like a pic or so

Step-by-step explanation:

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Step-by-step explanation:

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