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nata0808 [166]
2 years ago
14

What are the effects of global warming?​

Chemistry
1 answer:
svp [43]2 years ago
7 0

the effects are: temperature rises, water shortages, and increased fire threats

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Identify the precipitation reactions. drag the appropriate items to their respective bins.
lana66690 [7]
I can't fully answer this question because it is incomplete. In order for me to help you, I could just define what a precipitation reaction is and give a concrete example.

A precipitation reaction consists of two aqueous solutions that when reacted together, forms an insoluble salt. For example, 

AgNO₃ (aq) + HCl (aq) --> AgCl (s) + HNO₃ (aq)

In this case, the precipitate is AgCl, Silver Chloride, which appears as a white solid.
7 0
3 years ago
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Write an equation that shows the formation of a chromium(ii) ion from a neutral chromium atom.
daser333 [38]
The   equation  that  shows  the  formation  of  chromium (ii) ion  from  neutral  chromium  atom  is  as  follow
Cr ---> cr^2+   +  2e-
Cr^2+ is  the  chromium  ion   with  oxidation  state  of  two  which  is  one  of  the  common  ion  of  chromium.  Other  common  ion   of  chromium  include  chromium  of  oxidation  state  6  and  3

8 0
3 years ago
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Which type of molecule is shown below?
zubka84 [21]

Answer:

\boxed{\mathrm{Alkene}}

Explanation:

The hydrocarbon shown has a double bond. Hydrocarbons with double bonds are known as alkenes.

Cyclic alkanes have cyclic structure.

Alkanes only have single bonds.

Alkynes have triple bonds.

8 0
3 years ago
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Is zn2+ a transition metal?​
4vir4ik [10]

Answer:

Yes.

Explanation:

Zn2+ is the zinc ion in aqueous solution.

Zinc is a transition metal.

These metals are in the middle of the periodic table and have similar properties.

7 0
3 years ago
35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? A
dusya [7]

Given:

35.0 mL of acid with an unknown concentration

24.6 mL of 0.432 M base

Required:

Concentration of the acid

Solution:

M1V1 = M2V2

M1 (35.0 mL of acid) = (0.432 M base) (24.6 mL of base)

V1 = (0.432 M base) (24.6 mL of base) / (35.0 mL of acid)

M1 = 0.304 M of acid

5 0
3 years ago
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