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nata0808 [166]
2 years ago
14

What are the effects of global warming?​

Chemistry
1 answer:
svp [43]2 years ago
7 0

the effects are: temperature rises, water shortages, and increased fire threats

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How many moles are in 1.5 x 10^20 molecules of NH3?
Keith_Richards [23]
<span>Because the question is asking moles of NH3, the compound, any subscripts are irrelevant. It only wants to know how many moles of NH3 molecules, not individual atoms.

Therefore, we can simply convert to moles. 1.5x10^23/6.022x10^23 = .249 moles of NH3.

(If it were to ask moles of Hydrogen, for example, you would multiply the answer by 3, because there are 3 atoms of Hydrogen per one molecule of NH3. But this only asks for moles of the entire compound).  

hope you have a great day! :)
</span>
5 0
3 years ago
If an acid is added to different samples of buffered water, the sample with the
Helen [10]

Answer:

<h3><u>A). react with acid that is added and make a base.</u></h3>

explanation:

<em>Buffer solutions resist a change in pH when small amounts of a strong acid or a strong base are added.</em>

3 0
2 years ago
Read 2 more answers
When balancing a chemical equation, what are the large numbers that we adjust?
Nata [24]

Answer:

Coefficients

Explanation:

Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

H₂ + Cl₂     =>       HCl

Reactants:          Products:

2 hydrogen         1 hydrogen

2 chlorine            1 chlorine

Write the coefficient 2 in the products.

H₂ + Cl₂     =>       2HCl

Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.

6 0
3 years ago
553.5 mL ?:cm^3<br> how do i get my answer? and what is the answer?
dmitriy555 [2]

Answer:

553.5 cm3

Reason:

1 mL = 1 cm3

6 0
3 years ago
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
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