Answer:
C. It does not participate in a decay series.
Explanation:
From this statement, we can deduce that a radioisotope that forms a stable isotope after it undergoes radioactive decay suggests that it does not participate in a decay series.
- It could have emitted any form of radioactive particles which can be alpha or beta.
- We do not know if it has a long or short half life because the value is not given.
- But since the radioactive decay in one step produces a stable isotope, we can conclude that it did not participate in a decay series.
- A decay series involves a radioactive decay in multiple steps.
Answer:
Explanation:
Hello!
In this case, considering the given table, we are able to represent the symbolic rate law as shown below:
Thus, by using the following steps, we can find both m (BF3 order of reaction) and n (BF3 order of reaction):
- Experiment 1 and 2 for the calculation of n:
So we plug in to obtain:
So the order of reaction with respect to NH3 is 1.
- Experiment 3 and 4 for the calculation of m
So we plug in to obtain:
So the order of reaction with respect to BF3 is also 1.
Now, we can compute the rate constant by solving for it on any of the experiments there, say experiment 1:
Thus, the initial reaction rate for the 0.50M BF3 and 0.020M NH3 is:
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Answer:
58.3197 g/mol
Explanation:
hope it is correct and will help you
Answer:
a) B
b) A
c) B
d) A
Explanation:
If the strength of an inter-molecular force increases, then
vapour pressure decreases and boiling point increases
- Hence, B is a gas at 300 mmHg due to its low boiling point
- A has a higher boiling point because of its strong inter-molecular forces
- B has weaker inter-molecular forces due to its higher vapour pressure
- A has higher heat of vaporization, because it has strong inter-molecular forces
The total number of atoms : N = 8.95 x 10²²
<h3>Further explanation</h3>
Given
3 grams of Neon
Required
The number of atoms
Solution
mol of Neon :
= mass : Ar Neon
= 3 g : 20,1797 g/mol
= 0.1487
The number of atoms :
N = n x No(No=Avogaro's number)
N = 0.1487 x 6.02 x 10²³
N = 8.95 x 10²²