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nlexa [21]
3 years ago
7

What substance would you add to nahco3(aq) to form a buffer solution?

Chemistry
2 answers:
Nuetrik [128]3 years ago
8 0

Answer is: H₂CO₃.

This buffer is example of weak acid (H₂CO₃) and its conjugate base (HCO₃⁻).

Dissociation of carbonic acid: H₂CO₃(aq) ⇄ HCO₃⁻(aq) + H⁺(aq).

Adding acid: HCO₃⁻(aq) + H⁺(aq ⇄ H₂CO₃(aq).

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.  

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.  

ira [324]3 years ago
7 0
Buffer solution is made by mixing a weak acid with its conjugate base or weak base with its conjugate acid. NaHCO₃(aq) is a conjugate salt and also a conjugate base of H₂CO₃(aq) acid. Hence H₂CO₃(aq) should be added to make the buffer solution.
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This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

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Given the balanced equation representing a reaction:
sleet_krkn [62]
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Answer:

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