Answer:
Ld₂Mz
General Formulas and Concepts:
<u>Chemistry - Compounds</u>
- Valence shells
- Writing chemical compounds
- Balancing charges
Explanation:
<u>Step 1: Define</u>
"Lindenium" Ld w/ oxidation charge of +1
"Mendezine" Mz w/ oxidation charge of -2
<u>Step 2: Write Compound</u>
To balance out the charges to be neutral (0), we must counter balance the amount of Ld's with Mz's. We need 2 Ld's with 1 Mz to create a compound with a neutral charge:
2Ld¹⁺ + Mz²⁻
2(+1) + (-2) = (+2) + (-2) = 0 (neutral charge)
Therefore, our compound must be Ld₂Mz.
The binding energy of the electrons (also known as the work function of the surface) is determined as 2.43 x 10⁻¹⁹ J.
<h3>Binding energy of the electrons</h3>
The binding energy of the electrons is also known as work function of the metal and it is calculated as follows;
Ф = E - K.E
where;
Ф = hf - 86.2 kJ/mol
Ф = hc/λ - 86.2 kJ/mol
Ф = (6.63 x 10⁻³⁴ x 3 x 10⁸ )/515 x 10⁻⁹ - 86.2 kJ/mol
Ф = 3.86 x 10⁻¹⁹ J - (86200 J/mol)/(6.02 x 10²³)
Ф = 3.86 x 10⁻¹⁹ J - 1.43 x 10⁻¹⁹ J
Ф = 2.43 x 10⁻¹⁹ J
Learn more about work function here: brainly.com/question/19427469
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# of protons + # of neutrons = mass
9 + 10 = 19
the answer is D
2 NI₃= N₂ + 3 I₂
2 x 394.71 g --------------- 3 x 253.80 g
3.58 g ---------------------- ( mass of I₂ )
3.58 x 3 x 253.80 / 2 x 394.71 =
2725.812 / 789.42 => 3.4529 g of I₂
1 mole I₂ --------------- 253.80 g
?? ----------------------- 3.4529 g
3.4529 x 1 / 253.80 => 0.0136 moles of I₂
Answer C
hope this helps!
