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Semmy [17]
2 years ago
14

Two numbers have a sum of -15 and a product of -100. What are the numbers?

Mathematics
1 answer:
Bumek [7]2 years ago
4 0

Answer:

the numbers are -20 and 5

Step-by-step explanation:

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Substitute 3 for x and evaluate the expression below.
lana66690 [7]

Answer:4

Step-by-step explanation:3-8=-5. But because it is in absolute value, it would be positive 5. And then 5-1=4.

6 0
3 years ago
Which two are equivalent?
never [62]

Answer:

Expression I and IV

Step-by-step explanation:

Expression I simplified :

  • 3n + 7 + n + 4n
  • 8n + 7
  • Expression I = Expression IV
7 0
2 years ago
Make U the subject of the formula <br> D = ut + kt2
natali 33 [55]

Remark

I'm going to interpret this equation as

D = ut + kt²  The only difference is the 2.

Solution

Subtract kt² from both sides.

D - kt² = ut   Now divide by u on both sides.

\dfrac{D - kt^2}{t} = \dfrac{ut}{t}

The t's cancel out. on the right.  You are left with u on the right.

\dfrac{D - kt^2}{t} =\text{u}


6 0
3 years ago
Find the value of a and of b for which<br>(a) the solution of x2 + ax &lt; b is<br>-2&lt;x &lt; 4​
KengaRu [80]

Answer: a = -2

b = 8

Step-by-step explanation:

Given :

x^{2} +ax

re - writing the equation , we have

x^{2} +ax-b

we need to find the value of a and b for which -2<x < 4 , this means that the roots of the quadratic equation are -2<x < 4.

The formula for finding the quadratic equation when the roots are known is :

x^{2} - sum of roots(x) + product of root = 0

sum of roots = -2 + 4 = 2

product of roots = -2 x 4 = -8

substituting into the formula , we have:

x^{2} -2x-8=0 , which could be written in inequality form as

x^{2} -2x-8

comparing with x^{2} +ax-b , it means that :

a = -2

b = 8

3 0
3 years ago
Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?
Alja [10]

Answer:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: (a +b)^n, n > 0

Now, the BINOMIAL EXPANSION is the expansion which  describes the algebraic expansion of powers of a binomial.

Here, (a+b)^n  = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}

or, on simplification, the terms of the expansion are:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

The above statement holds for each  n > 0

Hence, the complete expansion for the given expression is given as above.

4 0
3 years ago
Read 2 more answers
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