Answer:
-5
Step-by-step explanation:
To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:
![\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}](https://tex.z-dn.net/?f=%5Cmathsf%7Bd%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%7D)
"d" represents the distance and coordinates are expressed as follows: (x, y)
Let's go to the calculations.
The answer is 10 uc.
a = interest rate of first CD
b = interest rate of second CD
and again, let's say the principal invested in each is $X.
![\bf a-b=3\qquad \implies \qquad \boxed{b}=3+a~\hfill \begin{cases} \left( \frac{a}{100} \right)X=240\\\\ \left( \frac{b}{100} \right)X=360 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \left( \cfrac{a}{100} \right)X=240\implies X=\cfrac{240}{~~\frac{a}{100}~~}\implies X=\cfrac{24000}{a} \\\\\\ \left( \cfrac{b}{100} \right)X=360\implies X=\cfrac{360}{~~\frac{b}{100}~~}\implies X=\cfrac{36000}{b} \\\\[-0.35em] ~\dotfill\\\\](https://tex.z-dn.net/?f=%5Cbf%20a-b%3D3%5Cqquad%20%5Cimplies%20%5Cqquad%20%5Cboxed%7Bb%7D%3D3%2Ba~%5Chfill%20%5Cbegin%7Bcases%7D%20%5Cleft%28%20%5Cfrac%7Ba%7D%7B100%7D%20%5Cright%29X%3D240%5C%5C%5C%5C%20%5Cleft%28%20%5Cfrac%7Bb%7D%7B100%7D%20%5Cright%29X%3D360%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cleft%28%20%5Ccfrac%7Ba%7D%7B100%7D%20%5Cright%29X%3D240%5Cimplies%20X%3D%5Ccfrac%7B240%7D%7B~~%5Cfrac%7Ba%7D%7B100%7D~~%7D%5Cimplies%20X%3D%5Ccfrac%7B24000%7D%7Ba%7D%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28%20%5Ccfrac%7Bb%7D%7B100%7D%20%5Cright%29X%3D360%5Cimplies%20X%3D%5Ccfrac%7B360%7D%7B~~%5Cfrac%7Bb%7D%7B100%7D~~%7D%5Cimplies%20X%3D%5Ccfrac%7B36000%7D%7Bb%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C)
![\bf X=X\qquad thus\qquad \implies \cfrac{24000}{a}=\cfrac{36000}{b}\implies \cfrac{24000}{a}=\cfrac{36000}{\boxed{3+a}} \\\\\\ (3+a)24000=36000a\implies \cfrac{3+a}{a}=\cfrac{36000}{24000}\implies \cfrac{3-a}{a}=\cfrac{3}{2} \\\\\\ 6-2a=3a\implies 6=5a\implies \cfrac{6}{5}=a\implies 1\frac{1}{5}=a\implies \blacktriangleright 1.2 = x\blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20X%3DX%5Cqquad%20thus%5Cqquad%20%5Cimplies%20%5Ccfrac%7B24000%7D%7Ba%7D%3D%5Ccfrac%7B36000%7D%7Bb%7D%5Cimplies%20%5Ccfrac%7B24000%7D%7Ba%7D%3D%5Ccfrac%7B36000%7D%7B%5Cboxed%7B3%2Ba%7D%7D%20%5C%5C%5C%5C%5C%5C%20%283%2Ba%2924000%3D36000a%5Cimplies%20%5Ccfrac%7B3%2Ba%7D%7Ba%7D%3D%5Ccfrac%7B36000%7D%7B24000%7D%5Cimplies%20%5Ccfrac%7B3-a%7D%7Ba%7D%3D%5Ccfrac%7B3%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%206-2a%3D3a%5Cimplies%206%3D5a%5Cimplies%20%5Ccfrac%7B6%7D%7B5%7D%3Da%5Cimplies%201%5Cfrac%7B1%7D%7B5%7D%3Da%5Cimplies%20%5Cblacktriangleright%201.2%20%3D%20x%5Cblacktriangleleft)
![\bf \stackrel{\textit{since we know that}}{b=3+a}\implies b=3+\cfrac{6}{5}\implies b=\cfrac{21}{5}\implies b=4\frac{1}{5}\implies \blacktriangleright b=4.2 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bsince%20we%20know%20that%7D%7D%7Bb%3D3%2Ba%7D%5Cimplies%20b%3D3%2B%5Ccfrac%7B6%7D%7B5%7D%5Cimplies%20b%3D%5Ccfrac%7B21%7D%7B5%7D%5Cimplies%20b%3D4%5Cfrac%7B1%7D%7B5%7D%5Cimplies%20%5Cblacktriangleright%20b%3D4.2%20%5Cblacktriangleleft)
Answer:
84 yards (don't forget to label, as my friend failed a test because of it!)
Hope this helps
Step-by-step explanation:
The total perimeter of the field is 358
The are length and widths...
the length is 95
but since there are two lengths...
its 95*2 which is 190
358-190=168
Since there are two widths...
168/2= 84
Answer: its 64
Step-by-step explanation: