Ask question

Ask question

All categories

3 years ago

5

A motorcycle drives up a steeply inclined ramp. The work done on the motorcycle by the earth’s gravitational force is ____.

2 answers:

sergejj [24]3 years ago

4 0

Answer: The work is negative

Explanation: The work is defined as the movement done by a force.

In this case, becuse the motocycle is driving upward in a inclinated ramp, the force of gravity will pull downwards, in the oposite direction of wich the motocycle is moving, this means that the work is negative, this means that the force is oposing to the motion of the motocycle and the motocycle needs to cancel this negative work in order to move.

PilotLPTM [1.2K]3 years ago

3 0

Negative - when the motorcycle displacement has a component in the opposite direction of the given force, that force is doing negative work on the motorcycle.

You might be interested in

A coin placed on the cover of a book just begins to move when the cover makes an angle of 38 degrees with the horizontal. What i

RSB [31]

Answer:

m g sin theta = force of object along incline due to gravity

N μ = frictional of incline on object where N is the normal force

N = m g cos theta force perpendicular to incline

m g sin theta = N μ = μ m g cos theta

μ = tan theta = tan 38 = .78

6 0

2 years ago

A block of mass 4 kilograms is initially moving at 5m/s on a horizontal surface. There is friction between the block and the sur

emmasim [6.3K]

• Net vertical force on the block:

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0

(<em>n</em> = magnitude of normal force, <em>w</em> = weight)

<em>n</em> = <em>w</em> = <em>m g</em>

(<em>m</em> = mass, <em>g</em> = 9.8 m/s²)

<em>n</em> = (4 kg) (9.8 m/s²) = 39.2 N

• Net horizontal force:

∑ <em>F</em> = -<em>f</em> = <em>m a</em>

(<em>f</em> = mag. of friction, <em>a</em> = acceleration)

We have <em>f</em> = <em>µ</em> <em>n</em> = 0.5 (39.2 N) = 19.6 N, so

-19.6 N = (4 kg) <em>a</em>

<em>a</em> = -4.9 m/s²

With this acceleration, the block comes to a rest from an initial speed of 5 m/s, so that it travels a distance ∆<em>x</em> in this time such that

0² - (5 m/s)² = 2 (-4.9 m/s²) ∆<em>x</em>

∆<em>x</em> = (25 m²/s²) / (9.8 m/s²) ≈ 2.55 m ≈ 2.6 m

8 0

3 years ago

A cart loaded with bricks has a total mass of 20.4 kg and is pulled at constant speed by a rope. The rope is inclined at 26.1 ◦

Readme [11.4K]

Answer:

Normal force, N = 154.5 N

Explanation:

Given that,

Total mass of the cart, m = 20.4 kg

Angle of inclination, $\theta=26.1^{\circ}$

Distance moved, d = 20.1 m

The coefficient of kinetic friction between ground and cart is 0.6

The value of acceleration due to gravity, $g=9.8\ m/s^2$

Let N is the normal force exerted on the cart by the floor. It is given by :

$N=mg-T\ sin\theta$

$T\ cos\theta=\mu N$

$T\ cos\theta=\mu (mg-T\ sin\theta)$

$T\ cos(26.1)=0.6 (20.4\times 9.8-T\ sin(26.1))$

T = 103.23 N

So, the normal force is :

$N=20.4\times 9.8-103.23\ sin(26.1)$

N = 154.5 N

So, the normal force exerted on the cart by the floor is 154.5 N. Hence, this is the required solution.

4 0

3 years ago

If two objects are in motion and have the same momentum, Object-A has a mass of 25 kg and a velocity of 2 m/s. What is the veloc

Alenkinab [10]

Answer:

5m/s

Explanation:

$Vb=Va\frac{ma}{mb} =2*\frac{25}{10} =5m/s$

6 0

3 years ago

Where do trees really come from and this is my little sister asking it not me

Hoochie [10]

The trees come from a seed and grow to trees

7 0

3 years ago

Read 2 more answers