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Tatiana [17]
3 years ago
14

A 1.00 cm diameter plastic sphere, used in a static electricity demonstration, has a charge of 22.6 pC uniformly distributed on

its surface. What is the potential at its surface (or just barely above it)?
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0

Answer:

Electric potential,  V = 40.68 volts

Explanation:

Given that,

Charge on the sphere, q=22.6\ pC=22.6\times 10^{-12}\ C

Diameter of the plastic sphere, d = 1 cm

Radius, r = 0.5 cm

We need to find the electric potential at its surface. The potential at a surface is given by :

V=\dfrac{kq}{r}

V=\dfrac{9\times 10^9\times 22.6\times 10^{-12}}{0.5\times 10^{-2}}

V = 40.68 volts

So, the electric potential at its surface is 40.68 volts. Hence, this is the required solution.

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A rubber ball and a lump of clay have equal mass. They are thrown with equal speed against a wall. The ball bounces back with ne
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Answer:

The ball experiences the greater momentum change

Explanation:

The momentum change of each object is given by:

\Delta p = m \Delta v= m (v-u)

where

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Both objects have same mass m and same initial velocity u. So we have:

- For the ball, the final velocity is

v=-u

Since it bounces back (so, opposite direction --> negative sign) with same speed (so, the magnitude of the final velocity is still u). So the change in momentum is

\Delta p=m(v-u)=m((-u)-u)=-2mu

- For the clay, the final velocity is

v=0

since it sticks to the wall. So, the change in momentum is

\Delta p = m(v-u)=m(0-u)=-mu

So we see that the greater momentum change (in magnitude) is experienced by the ball.

3 0
3 years ago
What si unit measures speed ?
dlinn [17]
Hmm doesnt soujd familiar
4 0
3 years ago
The greater the mass of an object, the greater the _____. (fill in question) ​
g100num [7]

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4 0
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Read 2 more answers
An acorn falls from a tree and hits the ground in 0.8 s. How far did the acorn fall . Use g = 9.8 m/s^2. Round your final result
mylen [45]

The distance covered by the acorn is 3.136 m.

<u>Explanation:</u>

The time taken for the acorn to hit the ground is 0.8 s. As it is a free fall, the acorn will be completely under the influence of gravity. So the acceleration will be acceleration due to gravity.

Then using the second law of equation,

s=ut+\frac{1}{2}gt^{2}

Since the initial velocity and time is zero, then the time taken to reach the ground is stated as 0.8 s, so

   s=0+\left(\frac{1}{2} \times 9.8 \times 0.8 \times 0.8\right)=\frac{6.272}{2}=3.136 \mathrm{m}

So the distance covered by the acorn is 3.136 m.

8 0
3 years ago
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