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3 years ago

1. Using the right triangle above, fill in the correct ratios for each trigonometric function. (do not simplify)

Mathematics

1 answer:

Juliette [100K]3 years ago

4 0

Seventy seven can write.

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A recipe for punch says to use

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5.76 cups of lemonade. 1.6x3.6

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3 years ago

Write and graph an equation in two variables that shows the relationship between the time t and the distance d traveled Moves 2

tiny-mole [99]

Answer:

the distance equation is

$d=\frac{2}{3}\times t$

Step-by-step explanation:

Let's assume

time in hours as 't'

distance traveled as 'd' meters

We are given

Moves 2 meters every 3 hours

So, firstly we find speed

$speed=\frac{2}{3}$

$k=\frac{2}{3}$

we know that

distance = (speed)*(time)

now, we can plug values

$d=k\times t$

now, we can plug value

$d=\frac{2}{3}\times t$

So, the distance equation is

$d=\frac{2}{3}\times t$

Graph:

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3 years ago

Chander earns a base pay of $2,200 per month. He also earns a commission of 4% of his total sales. One month Chander earned $2,4

soldi70 [24.7K]

X*0.6=200
So the answer is $333.33

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4 years ago

Read 2 more answers

What is the area of a rectangle when the length is 48 inches and height is 12 inches

monitta

Short Answer: The volume would be A=576 in²

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4 years ago

Read 2 more answers

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

inessss [21]

The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.

That is,

Consider X be the length of the pregnancy

Mean and standard deviation of the length of the pregnancy.

Mean $\mu =266\\$

Standard deviation \sigma =15

For part (a) , to find the probability of a pregnancy lasting 308 days or longer:

That is, to find $P(X\geq 308)$

Using normal distribution,

$z=\frac{X-\mu}{\sigma}$

$z=\frac{308-266}{15}$

$=\frac{42}{15}$

Thus $z=2.8$

So $P\left (X\geq 308 \right )=1-P(X$

$=1-P(z$

$=1-Table\: value\: of\: 2.8$

$=1-0.99744$

$=0.00256$

Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.

This the answer for part(a): 0.00256

For part(b), to find the length that separates premature babies from those who are not premature.

Given that the length of pregnancy is in the lowest 3%.

The z-value for the lowest of 3% is -1.8808

Then $X=\frac{X-\mu}{\sigma}\Rightarrow X=z*\sigma+\mu$

This implies $X=-1.8808*15+266=237.788$

Thus the babies who are born on or before 238 days are considered to be premature.

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3 years ago