The randomly selected subject is given bone density test which are normally distributed with mean =0 and standard deviation =1. It means bone density test score is standard normal variable.
The probability that a given score is less than 2.23
P(z < 2.23)
Using z score table to find probability below z=2.23
P(z < 2.23) = 0.9871
The probability that a given score is less than 2.23 is 0.9871
5 is the highest common factor
Neighborhood A :
first, put the numbers in order...
2,[2,2],4,(4),5,[5,5],5
5 number summary :
minimum = 2
Q1 = 2
Q2 (median) = 4
Q3 = 5
maximum = 5
IQR = Q3 - Q1......5 - 2 = 3...so the IQR = 3
Neighborhood B :
1,[1,2],2,(3),4,[5,5],12
5 number summary :
minimum = 1
Q1 = (1 + 2) / 2 = 3/2 or 1.5
Q2 (median) = 3
Q3 = 5
maximum = 12
IQR = Q3 - Q1....5 - 1.5 = 3.5
are the box plots symmetrical ?
Neighborhood A : the median is 4.....the minimum is 2....so thats 2 spaces from the median...the maximum is 5....so thats 1 space from the median...and being that they are not the same distance from the median, ur box plot is skewed to the left...so this is not symmetrical
Neighborhood B : the median is 3....the minimum is 1....so thats 2 spaces from the median...the maximum is 12....so thats 10 spaces from the median....these are not symmetrical especially since u have an outlier of 12....this is skewed to the right
The shape is closed because the sides touch.
I think is the answer because the right side =0 and so basically your left with the left side. 6(x² - 1)
