Answer:
u just put the number down those two numbers as the mode because the mode is whatever number occurs the most in a data set.
Step-by-step explanation:
Ex: 1,2,2,2,2,2,3,5
1,1,1,1,1,1,1,5,7,2,9 <u>answer</u>
Mode: 1 and 2
Answer:
B = 68° and C = 22°
Step-by-step explanation:
Let angle B's measure be B and angle C's measure be C.
Also note that complementary means that they sum to 90.
Now:
<u>The m∠B is two more than three times the measure of ∠C:</u>
we can write:
B = 3C + 2
<u>If ∠B and ∠C are complementary angles:</u>
B + C = 90
Putting 1st equation in 2nd, we get:
B + C = 90
3C + 2 + C = 90
4C = 90 - 2
4C = 88
C = 88/4 = 22
Now B = 3C + 2, so
B = 3(22) + 2 = 68
Hence, B = 68 degrees and C = 22 degrees
The last pair of numbers bracket the point 3/7.
12/32 = 3/8 < 3/7
15/18 = 5/6 > 3/7
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3/7 ≈ 0.428571... (repeating), so will be larger than 3/8 = 0.375, 12/32 = 3/8, and 4/10. That is, 3/7 is larger than the largest number of each pair except the last.
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You can always compare two fractions to see which is larger by cross-multiplying. That is a/b vs c/d gives the same result as ad vs bc. (Put the product on the numerator side of the comparison.)
Here, that would mean comparing 12/32 vs 3/7, we would get 12·7 vs 3·32, or 84 vs 96. The fraction on the left is smaller.
Comparing 3/7 vs 15/18, we would get 3·18 vs 7·15, or 54 vs 105. The fraction on the right is larger.
Answer:
<h2>D= 3.9 miles</h2>
Step-by-step explanation:
Given data
speed v= 13 miles per hour
time taken t= 20min to hour 0.3 hours
the distance D
We know that the relationship between speed, time, and distance
speed=distance/time
13=D/0.3
(the expression above describes the relationship between distance, speed, and time)
making D subject of formula we have
D= 0.3*13
D= 3.9 miles
hence the distance is 3.9miles
My mommmmmmmmmmmmmmmmmmmmmmmmmm
