Answer:
33
Step-by-step explanation:
The product of the secant segment lengths is a constant.
... TC×CV = UC×CW
... 14(2x+2) = 12(2x+5) . . . . substitute the values from the diagram
... 28x +28 = 24x +60 . . . . eliminate parentheses
... 4x = 32 . . . . . . . . . . . . . . add -28-24x
... x = 8 . . . . . . . . . . . . . . . . divide by 4
UW = 12 + 2x + 5 = 17+2·8 . . . . UW = UC + CW
UW = 33
Answer:
Step-by-step explanation:
Given that points scored is the dependent variable Y and Number of people attending the game is the independent variable is independent variable x
The correlation coefficient, slope and intercept are calculated as shown below:
x y
378 54
350 57
320 59
478 80
451 82
250 75
489 73
451 53
410 67
215 78
113 67
250 56
450 85
489 101
472 99
Mean 371.0666667 72.4
std dev 117.5138087 15.42632259
covariance 667.5733333
r 0.394558035
Slope 3.005642934
Intercept 153.4581182
y = 3.006x+153.46 is the regression line.
Corre = 0.3945 (weak positive)
Answer:
12:50 PM.
Step-by-step explanation:
We have been given that Craig’s school has 4 lessons in the morning and lesson 1 starts at 8:35. Each lesson is 60 minutes long. There is a break of 15 minutes between lesson 2 and 3.
We can see that lesson 1 will end at 9:35 AM and second lesson will end at 10:35 AM.
We have been also given that there is a break for 15 minutes between lesson 2 and 3. So third lesson will start at 10:50 AM as lunch break will end at 10:50 AM.
Third lesson will end 60 minutes after 10:50 AM that is 11:50 AM and fourth lesson will end 60 minutes after 11:50 AM that is 12:50 PM.
Therefore, 4th lesson will end at 12:50 PM.
The distance from the owl to the squirrel would be found by using the law of sins/co-sins
Cos (known angle) = adjacent leg / hypotenuse ( distance wanted)
cos(50) = 14 / x
x = 14 / cos50
x = 21.78 feet
The problem doesn't say if the answer should be rounded or not. You may have to round the answer if needed.
