Find <span>tan<span>(<span><span>5π</span>12</span>)</span></span> and sin ((5pi)/12)
Answer: <span>±<span>(2±<span>√3</span>)</span>and±<span><span>√<span>2+<span>√3</span></span></span>2</span></span>
Explanation:
Call tan ((5pi/12) = t.
Use trig identity: <span><span>tan2</span>a=<span><span>2<span>tana</span></span><span>1−<span><span>tan2</span>a</span></span></span></span>
<span><span>tan<span>(<span><span>10π</span>12</span>)</span></span>=<span>tan<span>(<span><span>5π</span>6</span>)</span></span>=−<span>1<span>√3</span></span>=<span><span>2t</span><span>1−<span>t2</span></span></span></span>
<span><span>t2</span>−2<span>√3</span>t−1=0</span>
<span>D=<span>d2</span>=<span>b2</span>−4ac=12+4=16</span>--> <span>d=±4</span>
<span>t=<span>tan<span>(<span><span>5π</span>12</span>)</span></span>=<span><span>2<span>√3</span></span>2</span>±<span>42</span>=2±<span>√3</span></span>
Call <span><span>sin<span>(<span><span>5π</span>12</span>)</span></span>=<span>siny</span></span>
Use trig identity: <span><span>cos2</span>a=1−2<span><span>sin2</span>a</span></span>
<span><span>cos<span>(<span><span>10π</span>12</span>)</span></span>=<span>cos<span>(<span><span>5π</span>6</span>)</span></span>=<span><span>−<span>√3</span></span>2</span>=1−2<span><span>sin2</span>y</span></span>
<span><span><span>sin2</span>y</span>=<span><span>2+<span>√3</span></span>4</span></span>
<span><span>siny</span>=<span>sin<span>(<span><span>5π</span>12</span>)</span></span>=±<span><span><span>√<span>2+<span>√3</span></span></span>2</span></span></span>
Answer: point form
1. (6,24)
2.(-4,-12)
3.(3,15)
4. (-5,-20)
5. (2,4)
6.(-1,-4)
7.(-3,-9)
8.(-4,-8)
9.(3,9)
10.(-6,-30)
Step-by-step explanation:
Answer:
A. 720 per hour
Step-by-step explanation:
1200+ <em>720</em> + 720 + <u>360</u> =3000
<em>hr 1↑</em>+ hr 2↑ + <u>↑30 min</u>
Answer:
m<ABO = 22 deg
Step-by-step explanation:
A tangent intersects a circle at the point of tangency making a right angle with the radius drawn to that point. That means that <BAO is a right angle and measures 90 deg. That makes the other two angles of the triangle complementary with a sum of 90 deg.
m<O + m<B = 90
68 + m<B = 90
m<B = 22
Answer: m<ABO = 22 deg
If we take the number of Zebras to be x and that of peacocks to be y
Then x + y = 14
A zebra has 4 legs while a peacock has 2 legs,
Therefore the total number of legs will be 4x + 2y which is equal to 36 .
Therefore, we have two equations
x + y = 14
4x + 2y = 36 solving them simultaneously using elimination
4x +2y = 36
2x + 2y = 28 ( multiplying the first equation by 2 to eliminate y)
2x = 8 ( subtracting the equations)
x = 4
y = 14 -(4)
= 10
Therefore, there are 4 zebras and 10 peacocks in the zoo