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Novosadov [1.4K]
3 years ago
5

How many 3 digit whole numbers are there between 99 and 1000

Mathematics
2 answers:
Elan Coil [88]3 years ago
6 0

Answer:

910

Step-by-step explanation:

netineya [11]3 years ago
3 0

Answer:

901

Step-by-step explanation:

1000 - 99 = 901

thats how you find the answer

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Marcus needs to buy some cabin. At the nearest store, three bags of cat food cost $16.50. How much would Marco spend on five bag
Bumek [7]

Answer:

$82.5

Step-by-step explanation:

$16.50 * 5 = $82.5

6 0
3 years ago
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(5x+3)(5x+3)gghhhhhhhh
Stella [2.4K]

Answer:

25x^2 + 30x + 9

8 0
2 years ago
880 ounces equals how many pounds?
julia-pushkina [17]

Answer:

880 oz= 55 lb

Step-by-step explanation:

have a good day

4 0
2 years ago
For a standard normal random variable, what z-score has (a) probability 0.175 to the right?
Mumz [18]
Answer: 0.935

Explanation: 

Let S = z-score that has a probability of 0.175 to the right. 

In terms of normal distribution, the expression "probability to the right" means the probability of having a z-score of more than a particular z-score, which is Z in our definition of variable Z. In terms of equation:

P(z ≥ S) = 0.175   (1)

Equation (1) is solvable using a normal distribution calculator (like the online calculator in this link: http://stattrek.com/online-calculator/normal.aspx). However, the calculator of this type most likely provides the value of P(z ≤ Z), the probability to the left of S.

Nevertheless, we can use the following equation:

P(z ≤ S) + P(z ≥ S) = 1 
⇔ P(z ≤ S) = 1 - P(z ≥ S)  (2)

Now using equations (1) and (2):

P(z ≤ S) = 1 - P(z ≥ S)
P(z ≤ S) = 1 - 0.175 
P(z ≤ S) = 0.825

Using a normal distribution calculator (like in this link: http://stattrek.com/online-calculator/normal.aspx),

P(z ≤ S) = 0.825
⇔ S = 0.935 

Hence, the z-score of 0.935 has a probability 0.175 to the right.
7 0
3 years ago
Need help with linear approximation
Dmitrij [34]
Consider a function f(x), the linear approximation L(x) of f(x) is given by

L(x)=f(a)+(x-a)f'(a)

Given the quantity: \frac{1}{203}

We approximate the quantity using the function f(x)= \frac{1}{x}, where x = 203.

We choose a = 200, thus the linear approximation is given as follows:

L(203)=f(200)+(203-200)f'(200) \\  \\ = \frac{1}{200} - \frac{3}{200^2} = \frac{200-3}{200^2} = \frac{197}{40,000} =0.004925
5 0
3 years ago
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