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Nikitich [7]
3 years ago
10

A bag contains counters that are red, black , or green . 1/3 of the counters are red 1/6 of the counters are black There are 15

green counters in the bag. How many black counters are in the bag ?
Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0

Answer:

There are 5 black counters in the bag.

Step-by-step explanation:

15 green counters in the bag

The proportion of green counters is given by:

p = 1 - (\frac{1}{3} + \frac{1}{6}) = 1 - (\frac{2}{6}+\frac{1}{6}) = 1 - \frac{3}{6} = 1 - \frac{1}{2} = \frac{2}{2} - \frac{1}{2} = \frac{1}{2}

So, we have that, the total is x. So

\frac{x}{2} = 15

x = 30

There are 30 total counters.

How many black counters are in the bag ?

A sixth of the counters are black. So

\frac{1}{6} \times 30 = \frac{30}{6} = 5

There are 5 black counters in the bag.

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Refer to the attached image.

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By applying exterior angle property of the triangle which states:

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