All categories

3 years ago

Nine times the sum of a number and 4 is 3. Use the variable w for the unknown number

Mathematics

1 answer:

DENIUS [597]3 years ago

6 0

9(w+4)=3
9w+36=3
w=-33/9

You might be interested in

According to the Triangle Inequality, the length of the longest side of a triangle must be less than the sum of the length of th

Tresset [83]

x has to equal 1. 3/10 + 1/5 = 1/2

the equation is now 1/2 + x = 1 1/2x

x = 1

1 1/2 = 1 1/2

4 0

3 years ago

Ellipse with vertices (0,+6) and passing through the point (2,2) what is the equation

Eddi Din [679]

The equation is Y=-2x+6

6 0

3 years ago

A members-only speaker series allows people to join for $28 and then pay $4 for every event attended. What is the total cost for

wariber [46]

Given:

Joining fee = $28

Fee of each event = $4

To find:

Total cost for someone to attend 4 events.

Solution:

Let the number of events be x and total fee be y.

Fee for 1 event = $4

Fee for x events = $4x

Joining fee remains constant. So, the total fee is

$y=28+4x$

Substitute x=4 in this equation.

$y=28+4(4)$

$y=28+16$

$y=44$

Therefore, total cost of 4 events is $44.

8 0

3 years ago

What is the value of n in the proportion below n/28 = 4/7

butalik [34]

n is 16

$\frac{n}{28} = \frac{4}{7} \\ n = \frac{4 \times 28}{7} = 16$

good luck

3 0

3 years ago

Read 2 more answers

Find ten rational numbers between -1 by 5 and 1 by 2

uysha [10]

Answer:

Step-by-step explanation:

First both the rational numbers should have same denominators. So, find least common denominator

Least common denominator is 10

$\frac{-1}{5}=\frac{-1*2}{5*2}=\frac{-2}{10}\\\\\\\frac{1}{2}=\frac{1*5}{2*5}=\frac{5}{10}\\\\\\$

Now multiply the numerator and denominators of the both the numbers by 10.

$\frac{-2*10}{10*10}= \frac{-20}{100} \ and \ \frac{5*10}{10*10}=\frac{50}{100}\\\\\\Now\ 10 \ rational \ numbers \ between\frac{-20}{10} \ and \ \frac{50}{100} \ is \\\\\\\frac{-19}{100},\frac{-18}{100},\frac{-17}{100},\frac{-16}{100}.\frac{-15}{100},\frac{-14}{100},\frac{-13}{100},\frac{-12}{100},\frac{-11}{100};\frac{-10}{100}$

8 0

3 years ago