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Elodia [21]
3 years ago
15

A tool set is on sale for 424.15$. The original price set was 499.00$. What percent of the original price is the sale price?

Mathematics
2 answers:
coldgirl [10]3 years ago
7 0
First you take the original set and subtract it by the sale set. After that you take you new answer and divide it by the original and you will get a percent that you can round too
SVEN [57.7K]3 years ago
4 0
( x = percent )

x/100 times 424.15/ 499

499x = 424.15
divide both sides by 499

x = 0.85 or 85%
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Write 4 3/5<br> as an improper fraction.
Andrews [41]

Answer:

\frac{23}{5}

Step-by-step explanation:

4 3/5

\frac{4 \times 5 + 3}{5}

\frac{20 + 3}{5}

= 23/5

8 0
3 years ago
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Luke bought a new jacket using a 10% off coupon. He paid $12.93 total, which inclues $1.43 in tax.
elixir [45]

Answer:

($14.37 was the original price)

Step-by-step explanation:

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The frequency distribution shows the number of registered motor vehicles for a random sample of 200 California households.
erastovalidia [21]

Answer:

1). Mean = 2.275

2). Median = 2 vehicles

Step-by-step explanation:

From the given table,

Number of vehicles (x)         Frequency (f)      (f)×(x)             Cumulative freq.

                  0                                    11                  0                           11

                  1                                     52                52                        63

                  2                                    66                132                      129

                  3                                    35                105                      164

                  4                                    19                  76                       183

                  5                                    12                  60                       195

                  6                                     5                  30                       200

                                                                          \sum (f\times x) = 455

Number of households = 200

Mean = \sum \frac{f.x}{n}

          = \frac{455}{200}

         = 2.275

Median = value of \frac{(n+1)}{2}th observation

             = value of \frac{201}{2}th observation

             = Value of 100.5th observation

             = Since 100.5th observation lies in the row of cumulative freq. = 129

             = 2

Therefore, median number of registered vehicles per California household

= 2 vehicles

6 0
3 years ago
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patriot [66]

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Zina [86]

Hi,

The answer you are looking for is 2. (-4,2)

Have a great day & remember to mark brainliest if I helped :)

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