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3 years ago

So this graph is showing us something but it’s asking to estimate #3 I don’t understand?

Mathematics

1 answer:

Genrish500 [490]3 years ago

4 0

You have to answer the first two questions, then graph the equation. Once you graph it, you will look on the x axis for 3 seconds, which is the last number listed on the axis, and the height is the corresponding y number

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Joey works 20 hours a week. If he works for 10 months continually, how many hours will he have worked? (1 month = 4 weeks)

Tcecarenko [31]

800 because 20*4*10=800 which means he works 80 weeks a month for 10 months

3 0

4 years ago

Help me plsx xndnjdsjjs

Kipish [7]

There is the answer hope it helpd if you can mark me brainliest

6 0

3 years ago

Factor each Polynomial<br> <img src="https://tex.z-dn.net/?f=a%5E%7B2%7D-4a-24%2B6a" id="TexFormula1" title="a^{2}-4a-24+6a" alt

Keith_Richards [23]

Answer:

Correct answer: (a - 4) · (a + 6)

Step-by-step explanation:

Given:

a² - 4a - 24 + 6a = a² - 4a + 6a - 24 = a (a - 4) + 6 (a - 4) = (a - 4) · (a + 6)

God is with you!!!

5 0

3 years ago

What is the answer to 16-2t=t+9+4t

Oliga [24]

Answer:

t=1

Step-by-step explanation:

16-2t=t+9+4t

Combine like term

16-2t = 5t+9

Add 2t to each side

16-2t +2t= 5t+2t+9

16 = 7t+9

Subtract 9 from each side

16-9 = 7t+9-9

7 = 7t

Divide each side by 7

7/7 = 7t/7

1=t

4 0

3 years ago

Read 2 more answers

Which expression is equivalent to the expression below? StartFraction 6 c squared 3 c Over negative 4 c 2 EndFraction divided by

Fudgin [204]

The given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

Given that, the expression can be written as.

$(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$

By simplifying the above equation,

$\dfrac{6c^2+3c}{-4c+2}\div \dfrac{2c+1}{4c-2}$

By taking out the common terms from the equation,

$\dfrac{3c(2c+1)}{2(-2c+1)}\div\dfrac{2c+1}{2(2c-1)}$

By simplifying the above equation by cancel out the common factors.

$\dfrac{3c}{-2c+1} \div \dfrac{1}{2c-1}$

Now, by taking (-1) common from (-2c+1) we get,

$\dfrac{3c}{-1(2c-1)} \div \dfrac{1}{2c-1}$

By simplifying the above equation, we get the expression,

$-3c$

So the given equation $(6c^2+3c)/(-4c+2)\div (2c+1)/(4c-2)$ is equivalent to the expression -3c.

For more details, follow the link given below.

brainly.com/question/1301963.

7 0

3 years ago