There are a total of 8 letters in student, with 6 different letters ( there are 2 s's and 2 t's).
First find the number of arrangements that can be made using 8 letters.
This is 8! which is:
8 x 7 x 6 x 5 x 4 3 x 2 x 1 = 40,320
Now there are 2 s's and 2 t's find the number of arrangements of those:
S = 2! = 2 x 1 = 2
T = 2! = 2 x 1 = 2
Now divide the total combinations by the product of the s and t's:
40,320 / (2*2)
= 40320 / 4
= 10,080
The answer is A. 10,080
Hope attachment helps (✿^‿^)
<span>
f(x)= −3/5x³</span><span>
The domain is all values x can be. There are no restrictions on x. it can be any real number (-∞ , ∞)
The range is all values y can be. There are noi restrictions on y either because the function is odd. y is </span><span>(-∞ , ∞)
The best answer is D.
domain (-∞, 0] ∪[0, ∞)
range </span><span>(-∞, 0] ∪[0, ∞) </span>
The graph is Parabola or Graph of Quadratic Function.
The graph has minimum value, not maximum. So ( A ) is not correct for maximum part.
B is not correct for exponential part.
also C is not correct for discrete part as Quadratic graph is continuous.
So the answer is D.
