For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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First you need to find the y-intercept, which is y = -1
Next is we need to find the slope of the line > you are going to have to do this by finding to clear point
The ones that I will be using are: (3, 1); (6, 3) (You could take any points)
Now using the slope formula we could find m.
m = y2-y1 / x2-x1
(1 - 3) / (3 - 6) = m
-2 / -3 = m
m = 2/3
Using the linear function format: y = mx + b
Therefore the equation of the line is y = 2x/3 -1
Answer:
The 2nd one would be different from the first because you are adding 3.
Step-by-step explanation:
The interest is simple
A=5,200×(1+0.04×5)
A=6,240