Answer: 64x^6/3
Step-by-step explanation:
(8x^3)^2/3
8^2(x^3)^3/3
64(x^3)^3/3
64x^6/3
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤
Answers:
13 42 m; B; 0.57 m
Step-by-step explanation:
Data:
Pool A: r = 22 ft
Pool B: D = 13.6 m
Calculations:
1. Radius of Pool A
r = 22 ft × (0.305 m/1 ft) = 6.71 m
2. Diameter of Pool A
D =2r = 2 × 6.71 = 13.42 m
The diameter of Pool A is 13.42 m.
3. Compare pool diameters
The diameter of Pool B is 13.6 m.
So, the diameter of Pool <u>B</u> is greater.
4. Compare circumferences
The formula for the circumference of a circle is
C = 2πr or C = πD
Pool A: C = 2π × 6.71 = 42.16 m
Pool B: r = π × 13.6 = 42.73 m
Pool B - Pool A = 42.73 - 42.16 = <u>0.57 m
</u>
The circumference is greater by <u>0.57 m.</u>
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
