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3 years ago

Write an expression andthen solve for x.149

Mathematics

1 answer:

MatroZZZ [7]3 years ago

3 0

X+52=149 x=97 hope this helped!

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2 years ago

Find the sum of the geometric sequence. 1, 1/2, 1/4, 1/8, 1/16

dezoksy [38]

I would convert them all to the denominator 16, due to the smallest fraction and all of them can be converted to it.

1 = 16/16
1/2 = 8/16
1/4 = 4/16
1/8 = 2/16
1/16 = 1/16

1+ 2 + 4 + 8 + 16 = 31

31/16 = 1 15/16

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3 years ago

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Please help with this

snow_lady [41]

Answer:

B. $- \frac{9}{8}$

Step-by-step explanation:

$\huge\frac{ - 2 {a}^{ - 3} {b}^{2} }{a} \\ \\ \huge = \frac{ - 2 {b}^{2} }{a \times{a}^{ 3} } \\ \\ \huge = \frac{ - 2 {b}^{2} }{{a}^{ 4} } \\ \\ \huge = \frac{ - 2 \times {3}^{2} }{ {( - 2)}^{4} } \\ \\ \huge= \frac{ - 2 \times 9}{16} \\ \\ \huge \red{= - \frac{9}{8} }$

8 0

2 years ago

Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).

Sever21 [200]

$\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta$

$\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}$

Since $\alpha$ lies in quadrant II, we have $\cos\alpha$ , so

$\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}$

$\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}$

$\beta$ lies in quadrant I, so $\sin\beta>0$ and

$\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}$

So

$\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}$

8 0

3 years ago

Write an expression andthen solve for x.149​

Write an expression andthen solve for x.149