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geniusboy [140]
3 years ago
5

Pete has $2.67 in dimes and pennies.If he has $1.16 in pennies how many dimes does Pete have

Mathematics
2 answers:
laiz [17]3 years ago
7 0

Answer: You get 15 dimes but 1 cent is left over leaving you with actually $1.17 in pennies, not $1.16.

mestny [16]3 years ago
3 0

Answer:15 17

Step-by-step explanation:

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PLEASE ANSWER THIS QUESTION,ILL MARK YOU AS THE BRAINLIEST IF UR ANSWER IS CORRECT.
Musya8 [376]

Answer:

I WILL SAY THE 2 ONE

Step-by-step explanation:

8 0
3 years ago
There are 125 members in the school
Igoryamba

Answer:

125x + 5,000 > 25,000

5 0
3 years ago
21, 89, 33, 53, 32, 51, 90, 69, 84<br>Median<br>Range<br>Mode<br>​
grigory [225]

Answer:

median 53

range 69

mode all values appear once

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(b+3)1/2+b1/2=3<br> A. b=0 and b= 2/3<br> B. b=1/4 and b=2<br> C. b=1<br> D. b=3
yan [13]
The answer is C Kay. Got it?
4 0
3 years ago
Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
solong [7]

Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.6 - 24.4}{1.2}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0
3 years ago
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