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7nadin3 [17]
3 years ago
10

What role do sources play in validating an argument? Are we able to rely on the internet to provide complete and truthful inform

ation? Of course not, but how do we discern? How do we determine the motives of the people we're reading? One thing we have learned is that the people screaming most loudly about dishonesty are the ones being most dishonest. That isn't by accident. So, what do you do? And how does that apply to this week's content?
Business
1 answer:
Andrej [43]3 years ago
8 0

Incomplete question. However, I answered from a general research perspective.

<u>Explanation:</u>

<em>What role do sources play in validating an argument?</em>

Well, the term source basically refers to the originator of any information. We have sources that are considered <em>credible sources</em> (like Encyclopedia, Journal Magazine, Newspaper, etc) and others that are considered <em>incredible sources </em>(general social media post). Knowing the kind of source could thus help validate an argument.

Relying on the internet to provide complete and truthful information is difficult considering the amount of fake news available today.

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The following is a partial year-end adjusted trial balance. Account Title Debits Credits Sales revenue $ 460,000 Loss on sale of
dalvyx [7]

Answer:

a) Operating Income = $73,000

b) Net income before income tax = $25,500

Explanation:

First part of the question is to determine the operating income or loss of the business

It is calculated as follows

Particulars                                          Amount

Sales Revenue                                  $460,000

Subtract: Cost of goods sold           ($240,000)

General and Administrative exp.       ($56,000)

Restructuring Costs                             ($58,000)

Selling Expenses                                  ($33,000)

Operating Income                             $73,000

Second part is to determine the income or loss before income taxes

Particulars                                            Amount

Operating Income                                 $73,000

Add: Interest Revenue                         $6,500

Deduct:Loss on sales of investment  ($54,000)

Income before Income Tax                  $25,500

Finally, the Net Income or loss after Income tax

$25,500 x .25 = $6,375

7 0
2 years ago
Question 25
telo118 [61]

Answer:

False

Explanation:

6 0
3 years ago
Three years ago, you invested $3,350.00. Today, it is worth $4,100.00. What rate of interest did you earn
Anastasy [175]

Answer:

6.97%

Explanation:

the formula to be used is

The formula for calculating future value:

FV = P (1 + r)^n

FV = Future value  

P = Present value  

R = interest rate  

N = number of years  

$4,100.00 = $3,350.00 x ( 1 + r)^3

divide both sides of the equation by $3,350.00

$4,100.00 / $3,350.00 = ( 1 + r)^3

1.223881 = ( 1 + r)^3

find the cube root of both sides

1.069661 = 1 + r

r = 6.97%

7 0
3 years ago
On March 1, Pimlico Corporation (a U.S.-based company) expects to order merchandise from a supplier in Sweden in three months. O
luda_lava [24]

Answer and Explanation:

The computation is shown below:

a. As a premium expense

= ($0.460 - $0.44) × 695,000

= $13,900

b. As a difference of 3 months spot rate and spot rate

= ($0.455 - $0.44) × 695,000

= $10,425

The first one represents the premium expense for $13,900 and the second part represents the adjustment to the net income in a positive way

7 0
2 years ago
A manufacturer estimates that its product can be produced at a total cost of C(x) = 50,000 + 100x + x3 dollars. If the manufactu
timofeeve [1]

Answer:

The level of production x that will maximize the profit is: 22,966

Explanation:

C(x) = 50,000 + 100x + x³

R(x) = 3400x

P(x) = R(x) - C(x)

      = 3400x - [50,000 + 100x + x³]

      = 3400x - 50,000 - 100x - x³

      = 3300x - 50,000 - x³   .................... (A)

P'(x) = 3300(1) - 0 - 3x²

       = 3300 - 3x²

At a critical point, P'(x) = 0

∴   0 = 3300 - 3x²

  3x² = 3300

    x² = 1100

     x = ± \sqrt{1100}

P"(x) = -6x

P(\sqrt{1100}) = -6 (\sqrt{1100})   < 0

by second derivative, 'P' max at    x = \sqrt{1100} = 33.17 (rounds)

since x =  \sqrt{1100} ,

recall that P(x) = 3300x - 50,000 - x³ from equation (A)

Therefore, Maximum Profit

P(\sqrt{1100}) = 3300\sqrt{1100} - 50000 - \sqrt{1100} ^{3}

              = 3300(33.17) - 50,000 - 33.17³

              = 109461 -50,000 - 36495.26

              = 22,965.74

Maximum profit is 22,966 to the nearest whole number

5 0
2 years ago
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