Speed of ball is 19.80 m/s .
<u>Explanation:</u>
We have , a 2.0 kg ball is resting at the top of a 20 m hill. if the ball rolls down the entire hill,We need to find how fast will it be going.Let's find out:
We know that,
Potential energy : This is the energy possessed by an object due to it's virtue of height and is given by , where m is mass , g is acceleration due to gravity & h is height !
Kinetic energy : This is the energy possessed by an object due to it's virtue of motion and is given by , where m is mass & v is the velocity of object !
By conservation of energy :
⇒
⇒
⇒
According to question , h=20 m i.e.
⇒
⇒
⇒
Hence , Speed of ball is 19.80 m/s .
Rolling without slipping means V=rw where w is angular velocity. So 4.0=0.1w
w=40rad/s
Answer:
Explanation:
the slits spacing, d = 0.21 mm
distance of screen, D = 61 cm
The condition for minima is given as
So, first minima, n = 0
fifth minima, n = 4
For small angle
From the figure:
okay u need to use the equation m=Fnet/a. Fnet=540N a=7.74m/s^2 m=540N/7.74m/s^2=69.77kg
What? I don’t understand what your question is what are you referring to could you please explain it