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julia-pushkina [17]
3 years ago
8

A vehicle accelerates from 0 to 30 m/s in 10 seconds on a straight road

Physics
2 answers:
Solnce55 [7]3 years ago
6 0
What's the question?

Tresset [83]3 years ago
3 0

Answer:

a = 3 m/s/s

Explanation:

Acceleration is defined as the rate of change in velocity

so we will have

a = \frac{v_f - v_i}{t}

so here we have

v_f = 30 m/s

v_i = 0

\Delta t = 10 s

now we have

a = \frac{30 - 0}{10}

a = 3 m/s^2

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A box weighing 43.2 N is pulled horizontally until it slides uniformly lat a constant
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Your diagram should include four forces:

• the box's weight, pointing down (magnitude <em>w</em> = 43.2 N)

• the normal force, pointing up (mag. <em>n</em>)

• the applied force, pointing the direction in which the box is sliding (mag. <em>p</em> = 6.30 N, with <em>p</em> for "pull")

• the frictional force, pointing oppoiste the applied force (mag. <em>f</em> )

The box is moving at a constant speed, so it is inequilibrium and the net forces in both the vertical and horizontal directions sum to 0. By Newton's second law, we have

<em>n</em> + (-<em>w</em>) = 0

and

<em>p</em> + (-<em>f</em> ) = 0

So then the forces have magnitudes

<em>w</em> = 43.2 N

<em>n</em> = <em>w</em> = 43.2 N

<em>p</em> = 6.30 N

<em>f</em> = <em>p</em> = 6.30 N

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A 4kg ball moving at 8m\sec
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Conservation of momentum: total momentum before = total momentum after

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Therefore β = 12.8 m/s
8 0
3 years ago
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