The letter refers to the shape of the orbital. The letters go in the order s, p, d, f, g, h, i, j, etc. The letters s, p, d, and f were assigned for historical reasons that need not concern us. All we have to do is remember the shapes that correspond to each letter.
hope this helps!
It would be 30 percent I think. Hope thats what you are looking for.
I will name block a as Ma=5 kg, block b as Mb=10 kg and mass of the pulley M=3 kg and radius as R. Since the system will accelerate in the direction of the block b because it has greater mass, I will take that direction as positive. Both blocks and the pulley have the same acceleration because the slipping on the pulley is neglected. First, the equations of motion:
Mb*g-Tg=MbαR and
Ta-Ma*g=MaαR,
where Ta and Tb are the tensions of the cord, g=9.81 m/s^2 and α is the angular accereration. Also a=αR where a is the acceleration of the system.
Now the equation of rotational dynamics of a solid body:
(Tb-Ta)R=Iα=(1/2)*M*R^2*α, where (1/2)*M*R^2 is the moment of inertia of a disc.
When we input Tb=Mb*g - Mb*α*R and Ta=Ma*g + Ma*α*R from the first two equations into the third we get: (Mb*g - Mb*α*R - Ma*α*R - Ma*g)*R=(1/2)*M*R^2*α.
We solve for α and get: α=(Mb*g-Ma*g)/((1/2)*MR+Mb*R+Ma*R)=2.97 rad/s^2.
We know that a=α*R and we easily get a=0.4455 m/s^2
You need to know the capacitance of the capacitor, C.
The voltage after time t is equal to the original voltage times e^(t/RC) where R is the resistance that you are trying to find.
Hello there!
The formula for Force is F = MA, or
Force = Mass x Acceleration
Well, since we have a rock falling in free fall, we can use the magical number 9.8 m/s^2 (also known as gravity). We have our value for force, 147N (Newtons).
So now, we have the value of our acceleration, A, and our value of the force, F, in our formula.
147 = 9.8M
To solve for M, we need to divide 147 by 9.8.
147/9.8 = 15
This means our Mass is 15 kg (remember your units!)
I hope this helps!