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3 years ago

A vehicle accelerates from 0 to 30 m/s in 10 seconds on a straight road

Physics

2 answers:

Solnce55 [7]3 years ago

6 0

What's the question?

Tresset [83]3 years ago

3 0

Answer:

a = 3 m/s/s

Explanation:

Acceleration is defined as the rate of change in velocity

so we will have

$a = \frac{v_f - v_i}{t}$

so here we have

$v_f = 30 m/s$

$v_i = 0$

$\Delta t = 10 s$

now we have

$a = \frac{30 - 0}{10}$

$a = 3 m/s^2$

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2 years ago

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3 years ago

The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag

CaHeK987 [17]

The speed of tsunami is a.0.32 km.

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2 years ago

A 20 μF capacitor initially charged to 30 μC is discharged through a 1.5 kΩ resistor. Part A How long does it take to reduce the

Natasha_Volkova [10]

Answer:

it will take 36.12 ms to reduce the capacitor's charge to 10 μC

Explanation:

Qi= C×V

then:

Vi = Q/C = 30μ/20μ = 1.5 volts

and:

Vf = Q/C = 10μ/20μ = 0.5 volts

then:

v = v₀e^(–t/τ)

v₀ is the initial voltage on the cap

v is the voltage after time t

R is resistance in ohms,

C is capacitance in farads

t is time in seconds

RC = τ = time constant

τ = 20µ x 1.5k = 30 ms

v = v₀e^(t/τ)

0.5 = 1.5e^(t/30ms)

e^(t/30ms) = 10/3

t/30ms = 1.20397

t = (30ms)(1.20397) = 36.12 ms

Therefore, it will take 36.12 ms to reduce the capacitor's charge to 10 μC.

7 0

3 years ago