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2 years ago

Two consecutive even integers have a sum of 67. Find the integers.

Mathematics

1 answer:

jeka942 years ago

6 0

Answer:

33, 34

Step-by-step explanation:

the problem statement is competent confusing. is that really what your teacher asked you ?

adding two even integer numbers (it did not matter which ones) always result in an even number.

67 is uneven.

so it cannot be the result of 2 even numbers. "consecutive" or not. let alone the fact that 2 even numbers cannot actually be consecutive, because there is always an uneven number after each even number. but with some eyes closed one can understand that this could have meant "an even number and the next even number after that". but still, my first point is a real blocker.

so, I decided to ignore "even" and went for "two consecutive numbers".

x + (x+1) = 67

2x + 1 = 67

2x = 66

x = 33

x+1 = 34

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Answer for 14+3y < 65

ivanzaharov [21]

Hey there!

14 + 3y < 65

SOME people replace “<”, “>”, “≥”, or “≤” as an equal sign (=) to make it easier to solve

14 + 3y < 65
14 + 3y = 65

SUBTRACT by 14 on both of your sides
3y + 14 - 14 = 65 - 14
CANCEL out: 14 - 14 because that gives you 0
KEEP: 65 - 14 because it helps you solve for “y”

**65 - 14 = 51**

NEW EQUATION: 3y = 51

DIVIDE by 3 both of your sides
3y/3 = 51/3
CANCEL out: 3/3 because that gives you 1
KEEP: 51/3 because it gives you the value of “y”

NEW EQUATION: y = 51/3

**51/3 = 17**

Answer: y = 17 ☑️

☑️ OVERALL ANSWER FOR YOU: y < 17 ☑️
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2 years ago

Which of the following are solutions to the equation below 4x^2+20x+25=49

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3 years ago

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Solve T=C(5+ AB) for B.

Vaselesa [24]

Answer:

$b = \frac{t - 5}{a}$

Step-by-step explanation:

$t = c(5 + ab)$

Simplify:

$t = 5c + abc$

Move 5c to the other side:

$t - 5c = abc$

Divide bother sides with AC:

$\frac{t - 5c}{ac} = \frac{abc}{ac}$

Simplify:

$\frac{t - 5}{a} = b$

If this answer helped you, give this answer a heart, rate it and if you could then please mark it brainliest. Thanks!

8 0

1 year ago

Based on aâ poll, among adults who regret gettingâ tattoos, 18â% say that they were too young when they got their tattoos. Assum

Sergeeva-Olga [200]

Answer:

a) 20.44% probability that none of the selected adults say that they were too young to get tattoos.

b) 35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) 56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d) No

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they say they were too young when they got their tattoos, or they don't say that. Each adult is independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

18% say that they were too young when they got their tattoos.

This means that $p = 0.18$

Eight adults who regret getting tattoos are randomly selected

This means that $n = 8$

a. Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.18)^{0}.(0.82)^{8} = 0.2044$

20.44% probability that none of the selected adults say that they were too young to get tattoos.

b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{8,1}.(0.18)^{1}.(0.82)^{7} = 0.3590$

35.90% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c. Find the probability that the number of selected adults saying they were too young is 0 or 1.

Either a. or b.

20.44 + 35.90 = 56.34

56.34% probability that the number of selected adults saying they were too young is 0 or 1.

d. It we randomly select 9 adults. Is 1 a significantly low number who day that they were too young to get tattoos?

Now $n = 9$

It is significantly low if it is more than 2.5 standard deviations below the mean.

The mean is $E(X) = np = 9*0.18 = 1.62$

The standard deviation is $\sqrt{V(X)} = \sqrt{n*p*(1-p)} = \sqrt{9*0.18*0.82} = 1.15$

1 > (1.62 - 2.5*1.15)

So the answer is no.

5 0

2 years ago

Two consecutive even integers have a sum of 67. Find the integers.​

Two consecutive even integers have a sum of 67. Find the integers.