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Katyanochek1 [597]
3 years ago
9

What is the equation of a line with slope 4 and passes through point (4,2)?

Mathematics
1 answer:
bezimeni [28]3 years ago
4 0

Answer:

y = 4x - 14

Step-by-step explanation:

Use point-slope form and substitute the values.

y - 2 = 4(x - 4)

y - 2 = 4x - 16

y = 4x - 14

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GREYUIT [131]

Answer:

First choice

-∞ < y< ∞

Step-by-step explanation:

In this function,we need to use graph in order to find out the range.

Graph is attached.

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6 0
2 years ago
Which of the following is the solution to the differentiable equation dy/dx=4x/y, where Y(2)=-2
aliya0001 [1]

First we'll substitute \frac{dy}{dx} with y'

y'=\frac{4x}{y}

Then we can separate this.

yy'=4x

Then we'll solve this.

yy'=4x: \frac{y^2}{2}=2x^2+c_1

\frac{y^2}{2}=2x^2-6

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Then we'll plug in to find the extraneous solutions (if any)

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7 0
3 years ago
Find the tenth term in the sequence: 12,10,8,...<br> a) -10<br> b) -6<br> c) -8<br> d) -18
raketka [301]
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6 0
3 years ago
Read 2 more answers
This is a one step equation
vichka [17]

Awnser:

I think its 7

Step-by-step explanation:

the photo is blurly can you say it and i can help u again

3 0
3 years ago
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Answer correctly please
Paul [167]

Answer:

\$272,49

Step-by-step explanation:

7. \displaystyle /text{The answer makes sense because since the depreciation rate is 15%, we know that we need to use the "exponential decay" formula.}

6. \displaystyle /text{After a depreciation rate of 15% for the past 8 years, the stock is now worth approximately $272,49.}

5. \displaystyle 1000[0,85]^8 = 272,490525 ≈ \$272,49

4. \displaystyle 1000 = a \\ -15\% + 100\% = 1 - r; 85\% = 1 - r \\ 8\:years = time\:[t]

3. \displaystyle /text{We need to use the "Exponential Decay" formula} - f(t) = a[1 - r]^t, where a > 0

2. \displaystyle /text{How much is the stock worth after a depreciation rate of 15% per year?}

1. \displaystyle /text{initial amount: $1000, a depreciation rate of 15%, and a time period of 8 years}

I am joyous to assist you anytime.

5 0
3 years ago
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