3/8. To get this answer you need to multiply the numerators and the denominators. 1 x 3 is equal to 3 and 2 x 4 is qual to 8. Therefore, 3/8
Answer:
Step-by-step explanation:
A circle with radius r and centre (a, b) has an equation:
6x+15y=-45
<span>6x+5y=-35
subtract second equation from the first
</span>6x+15y=-45
<span>6x+5y=-35
</span><u>- - +
</u> 10y = -10
⇒ y = (-10/10) = 1
put value of y in one of the equation,
6x+5y = -35
⇒ 6x + 5(-1) = -35
⇒ 6x - 5 =-35
⇒ 6x = -35 + 5 = 30
⇒ x = 30/6
⇒ x = 5
So x=5 and y=-1.
Answer:
x=10
Step-by-step explanation:
set it up and solve
2x-1=x+9
2x=x+10
x=10
Part A
4 < 5 < 9 is given to us. Apply the square root to each term to end up with this inequality: sqrt(4) < sqrt(5) < sqrt(9)
So sqrt(5) is between <u>sqrt(4)</u> and <u>sqrt(9)</u>
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Part B
Simplify those two mentioned square roots
sqrt(4) = sqrt(2^2) = 2
sqrt(9) = sqrt(3^2) = 3
Therefore, sqrt(5) is also between <u>2</u> and <u>3</u>
We can see this through using a calculator: sqrt(5) = 2.23607 approximately
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Part C
We can now say:
2 < sqrt(5) < 3
Multiply all three sides by 6
6*2 < 6*sqrt(5) < 6*3
So the expression 6*sqrt(5) is between <u>6 x 2</u> and <u>6 x 3</u>
Sure enough, a calculator confirms this
6*sqrt(5) = 13.416408
since 6*2 = 12 and 6*3 = 18. We see that 13.416 is between 12 and 18.