I just did this problem on e2020 and its
1.SAS
2.CPCTC
Answer:
meter
Step-by-step explanation:
We have to write first what is known from the information.
Let's say, length is L, width is W, and height is H
1. The length of the box is 2 1/2 m = 2,5 m = 5/2 m, it is 1 9/16 = 25/16 times it's width (L). So we have the equation :
L ≡ ![\frac{5}{2} = \frac{25}{16} W](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%3D%20%5Cfrac%7B25%7D%7B16%7D%20W)
Then we find the W. From the fraction above, we found W equals to
meter
2. What is the height of the box, if its volume is 12 3/4 m^3 = 51/4 m^3
Formula of a volume is :
The area wide times the height
In this problem, the equation is :
L × W × H = Volume
Insert the numbers,
×
× H = ![\frac{51}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B51%7D%7B4%7D)
From the fraction above, we can find that H equals to
meter
Answer:
It's about 3 feet
Step-by-step explanation:
Answer: Median Mode Mean
Step-by-step explanation:
A normal distribution a symmetric distribution where most of the values lies around the central peak where Mean, median mode all lies together and the value of z=0 (as z-value given the distance of data values from mean with respect to the standard deviation).
i.e. Z-score of 0 has 50% of the area to the left and 50% area to the right.
Hence, at a z-score of 0.0 in a normal distribution Mean, Median and Mode all fall together.
Answer:
0.00109
Step-by-step explanation:
1.09(10^−3)
=1.09*10^−3
=1.09*
1
/10*10*10
=0.00109