The answer is x=-3
5-x=11+x
-11 -11 First subtract 11
-6-x=x
+x +x Now add x to both sides
-6=2x
~2 ~2 Finally divide by 2
-3=x Your answer is x=-3
Answer:
9
Step-by-step explanation:
Answer:
- zeros: x = -3, -1, +2.
- end behavior: as x approaches -∞, f(x) approaches -∞.
Step-by-step explanation:
I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.
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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...
x² +x -6
which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.
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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).
Answer:
Ans: (-5, 5)
-5 < x < 5
Step-by-step explanation:
Standard form: f(x) = x^2 - 25 < 0.
First solve x^2 - 25 = 0 --> x = +- 5
Use the algebraic method to solve f(x) < 0. Between the 2 real roots (-5) and (5), f(x) < 0, as opposite in sign to a = 1.
Answer by open interval: (-5, 5)