Answer:
35
Step-by-step explanation:
7 orchids can be lined as 7!. This means that for the first orchid of the line, you can select 7 options. When you place the first orchid, for the second option you can select among 6 since 1 orchid has already been placed. Similarly, for the 3rd orchid of the line, you have left 5 options. The sequence goes in this fashion and for 7 orchids, you have 7*6*5*4*3*2*1 possibilities. However, there is a restriction here. 3 of the orchids are white and 4 are levender. This means that it does not make a difference if we line 3 white orchids in an arbitrary order since it will seem the same from the outside. As a result, the options for lining the 7 orchids diminish. The reduction should eliminate the number of different lining within the same colors. Similar to 7! explanation above, 3 white orchids can be lined as 3! and 4 levender orchids can be lined as 4!. To eliminate these options, we divide all options by the restrictions. The result is:
= 35. [(7*6*5*4*3*2*1/(4*3*2*1*3*2*1)]
9 dollars represents 90% of the cost. Divide 9 by 0.90 to get the original price, 10 dollars
Hi there! I can help you with this! First, let's combine like terms and do everything for the right side of the problem. When you do the distributive property, you get 32x - 40. Combine like terms and you'll get 32x - 60. Now, the inequality is 20x = 32x - 60. First, let's subtract 32x from both sides to get the integer by itself. When you do that, you get -12x = -60. Now, divide each side by -12 to isolate the "x". -60/-12 is 5. Let's plug it in. 20 * 5 is 100. 32 * 5 is 160. 160 - 60 is 100. 100 = 100. There. x = 5.
6 is one of the six total sides on a dice.
P(6)=1/6
1 is one of the six total sides on a dice.
P(1)=1/6
Answer:
hi
Step-by-step explanation:
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