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GrogVix [38]
2 years ago
12

You can buy an 8-pack of paper towels for $7.92 or a 12-pack for $11.64. Which is the better buy?

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
8 0

Answer:

ill say the 8 pack

Step-by-step explanation:

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a circle has a radius of 4. an arc in this circle has a central angle of 288. what is the length of the arc?
anzhelika [568]

Answer:20.096

Step-by-step explanation:

radius =r=4

Φ=288

π=3 14

Length of arc=Φ/360 x 2 x π x r

Length of arc=288/360 x 2 x 3.14 x 4

Length of arc=0.8 x 2 x 3.14 x 4

Length of arc=20.096

8 0
3 years ago
Work out the equation of the line which has a gradient of -2 and passes through the point (1,7)
Ilya [14]

point slope form of a line

y-y1 = m(x-x1)

y-7 = -2 (x-1)

if you want it in slope intercept form

y-7 = -2x +2

add 7 to each side

y = -2x +9

5 0
3 years ago
Solve x/2 - 3 = 7<br> A. 5<br> B. 10<br> C. 20<br> D. 40
12345 [234]

Answer:

The answer is C.

Step-by-step explanation:

Add 3 to both sides and you will get x/2=10. Multiply by the reciprocal on both sides making x=20.

4 0
3 years ago
Read 2 more answers
4 girls and 2 boys are working on an art project they have four square pieces of felt if each person gets an equal share of the
maksim [4K]

(4 pieces) / (6 kids)  =  (4/6) (pieces/kids)  =  2/3 piece/kid

5 0
3 years ago
Ann has 30 jobs that she must do in sequence, with the times required to do each of these jobs being independent random variable
IgorLugansk [536]

Answer:

P(T_A < T_B) = P(T_A -T_B

Step-by-step explanation:

Assuming this problem: "Ann has 30 jobs that she must do in sequence, with the times required to do each of these jobs being independent random variables with mean 50 minutes and standard deviation 10 minutes. Bob has 30 jobs that he must do in sequence, with the times required to do each of these jobs being independent random variables with mean 52 minutes and standard deviation 15 minutes. Ann's and Bob's times are independent. Find the approximate probability that Ann finishes her jobs before Bob finishes his jobs".

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can create some notation.

Let A the values for Ann we know that n1 = 30 jobs solved in sequence and we can assume that the random variable X_i the time in order to do the ith job for i=1,2,....,n_1. We will have the following parameters for A.

\mu_A = 50, \sigma_A =10

W can assume that B represent Bob we know that n2 = 30 jobs solved in sequence and we can assume that the random variable [tex[X_i[/tex] the time in order to do the ith job for i=1,2,....,n_2. We will have the following parameters for A

\mu_B = 52, \sigma_B =15

And we can find the distribution for the total, if we remember the definition of mean we have:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

And T =n \bar X

And the E(T) = n \mu

Var(T) = n^2 \frac{\sigma^2}{n}=n\sigma^2

So then we have:

E(T_A)=30*50 =1500 , Var(T_A) = 30*10^2 =3000

E(T_B)=30*52 =1560 , Var(T_B) = 30 *15^2 =6750

Since we want this probability "Find the approximate probability that Ann finishes her jobs before Bob finishes his jobs" we can express like this:

P(T_A < T_B) = P(T_A -T_B

Since we have independence (condition given by the problem) we can find the parameters for the random variable T_A -T_B

E[T_A -T_B] = E(T_A) -E(T_B)=1500-1560=-60

Var[T_A -T_B]= Var(T_A)+Var(T_B) =3000+6750=9750

And now we can find the probability like this:

P(T_A < T_B) = P(T_A -T_B

P(\frac{(T_A -T_B)-(-60)}{\sqrt{9750}}< \frac{60}{\sqrt{9750}})

P(Z

7 0
3 years ago
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