yes because they are inert or inactive at normal temperature, they are inactive because their outer most orbit contain either 2 or 8 electrons.that make them stable
All those compounds are ionic.
Then they dissociate into ions when they are in water.
I will write the dissociation equations. The charges of the ions is indicated inside parenthesis.
KI -> K (+) + I (-) => two ions
K2SO4 -> 2 k(+) + SO4 (2-) -> three ions
NaCl -> Na(+) + Cl(-) => two ions
KBr -> K(+) + Br(-)
As you se every molecule of the compound K2SO4 dissociates into three ions, while the other compounds dissociate into two ions. Given that the decrase in the freezong point of water is proportional to the number of particles dissolved, the K2SO4 will lower the freezing point the most.
Answer: option B. K2SO4
Answer:
Explanation:
Assume the reaction is the combustion of propane.
Word equation: propane plus oxygen produces carbon dioxide and water
Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)
Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)
(a) Table of enthalpies of formation of reactants and products
(b)Total enthalpies of reactants and products
ΔᵣH° is negative, so the reaction is exothermic.
Answer:
[H₃O⁺] = 6.31 x 10⁻³ M.
Explanation:
- To find the hydronium ion concentration [H₃O⁺], we can use the relation:
<em>pH = - log[H₃O⁺].</em>
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∴ 2.2 = - log[H₃O⁺].
∴ log[H₃O⁺] = - 2.2
<em>∴ [H₃O⁺] = 6.31 x 10⁻³ M.</em>
Lemonade mix and water
Solvent: Water
Solute: Lemonade mix
