Answer: 0.17M
Explanation:
The equation for the reaction is :
2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O
From the balanced equation, we obtain :
nA = mole of acid = 2
nB = mole of the base = 1
From the question, we obtain:
Va = Vol. Of acid = 0.105L
Ma = conc. Of acid =?
Vb = Vol of base = 35.7 mL = 0.0357L
Mb = conc. of base = 0.25M.
We solve for the conc. of the acid using:
MaVa / Mb Vb = nA / nB
(Ma x 0.105) / (0.25x0.0357) = 2
Cross multiply to express in linear form. We have:
Ma x 0.105 = 0.25 x 0.0357 x 2
Divide both side by 0.105. We have
Ma = (0.25 x 0.0357 x 2) / 0.105
Ma = 0.17M
Therefore the concentration of the acid(HNO3) is 0.17M
