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adelina 88 [10]
3 years ago
7

If a mixture of gasses contain 4.5 atmospheric O2 and 785mm Hg of N2 what is the total pressure of the mixture in atm

Chemistry
1 answer:
Triss [41]3 years ago
6 0

Answer:

The total pressure of the mixture is 5, 53 atm.

Explanation:

The sum of the partial pressures of the gases that make up a gaseous mixture is equal to the total pressure of said mixture, according to Dalton's law. We convert the unit of pressure in mmHg into atm:

760 mmHg----1 atm

785 mmHg----x= (785 mmHgx 1 atm)/760 mmHg=1, 03 atm

P total= P 02 + P N2

P total= 4, 5 atm + 1,03 atm=5, 53 atm

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3 years ago
The smallest units of matter that normally CANNOT be broken down are atoms. molecules. cells. phospholipids.
olya-2409 [2.1K]

Answer: atoms

Explanation:

All matter is made up of smaller indivisible particles called atoms. These atoms are the smallest units of matter ACCORDING to the Dalton's Atomic theory.

Molecules are combined atoms, while cells and phospholipids are complex combination of atoms.

Therefore, atoms is the answer

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3 years ago
4. Energy can be conserved by -
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Energy can be conserved by efficient energy use.

Answer: Option A

<u>Explanation:</u>

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3 years ago
How many moles of aluminum oxide (Al2O3) can be produced from 12.8 moles of oxygen gas (02)
zhannawk [14.2K]

Answer:

Theoretical Yield

Percent yield

Example stoichiometry problem

How much oxygen can be prepared from 12.25 g KClO3 . (Use molar mass KClO3 = 122.5 g.)

Most stoichiometry problems can be solved using the following steps.

Step 1.

Write and balance the equation for the decomposition of KClO3 with heat (∆). 2KClO3 + ∆ → 2KCl + 3O2

Step 2.

Convert what you have (in this case g KClO3) to moles.

# moles = grams/molar mass = 12.25 g /122.5 = 0.100 mole KClO3.

Step 3.

Using the coefficients in the balanced equation, convert moles of what you have (moles KClO3) to moles of what you want (in this case moles oxygen).

0.100 mol KClO3 x (3 moles O2/2 moles KClO3) = 0.100 x (3/2) = 0.150 mole O2.

Step 4.

Convert moles from step 3 to grams.

moles x molar mass = grams

0.150 mole O2 x (32.0 g O2/mole O2) = 4.80 g O2 produced from 12.25 g KClO3. This is the theoretical yield. If the ACTUAL yield is 4.20 grams, calculate percent yield. Percent yield = (actual yield/theoretical yield) x 100 = (4.20/4.80) x 100 = 87.5% yield

NOTE: In step 1, moles can be obtained other ways; in step 4 moles can be converted to other units.

a. For solutions, M x L = moles (or mL x M = millimoles).

b. For gases, L/22.4 = moles

4 0
3 years ago
Circle the atom with the largest atomic radius in each group
Dominik [7]

Answer:

The atomic radius increases down the group because more shell are added

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O>F

Br>Cl

Mg>Ca

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3 years ago
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