12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇
<h3>Explanation</h3>
Balance by the conservation of atoms.
Assign coefficient <em>1 </em>to the species with the largest number of elements and atoms. H₃PO₄ contains three elements. Each of its molecule contains eight atoms, that's two more than the six atoms in a HClO₄ molecule. Start by assigning H₃PO₄ a coefficient of <em>1</em>.
? HClO₄ + ? P₄O₁₀ → <em>1</em> H₃PO₄ + ? Cl₂O₇
There are now three H atoms, one P atom on the product side. H₃PO₄ is the only product that contains H and P atoms. As a result, there should be the same number of H and P atoms on the reactant side.
- Among all reactants, only HClO₄ contains H atoms. Each HClO₄ molecule contains one H atom. Three H atoms correspond to three HClO₄ molecule.
- Among all reactants, only P₄O₁₀ contains P atoms. Each P₄O₁₀ molecule contains four P atoms. One P atom corresponds to 1/4 of a P₄O₁₀ molecule.
Thus
<em>3</em> HClO₄ + <em>1/4</em> P₄O₁₀ → <em>1</em> H₃PO₄ + ? Cl₂O₇
There are three Cl atoms in three HClO₄ molecules. HClO₄ is the only species that contains Cl among all reactants. There are three Cl atoms on the reactant side and shall be the same number of Cl atoms on the product side.
- Cl₂O₇ is the only molecule that contains Cl among the products. Each Cl₂O₇ molecule contains two Cl atoms. Three Cl atoms will correspond to 3/2 Cl₂O₇ molecules.
<em>3</em> HClO₄ + <em>1/4</em> P₄O₁₀ → <em>1</em> H₃PO₄ + <em>3/2</em> Cl₂O₇
Multiply both sides by the least common multiple of the denominators to eliminate the fraction. The least common multiple in this case is four.
12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇
Answer: Boyle's Law
Explanation:
Boyle's Law which is also called Mariotte's law was formulated by physicist Robert Boyle in 1662.
It posits that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.
As the Scuba Diver went deeper, the volume of air dropped so the pressure increased.
Please do react or comment to the answer if you have any issues or if you feel like this helped you so we can help others as well. Thank you.
moles NaOH = c · V = 0.1973 mmol/mL · 29.43 mL = 5.806539 mmol
moles H2SO4 = 5.806539 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.9032695 mmol
Hence
[H2SO4]= n/V = 2.9032695 mmol / 32.42 mL = 0.08955 M
The answer to this question is [H2SO4] = 0.08955 M
Answer:
Average atomic mass of carbon = 12.01 amu.
Explanation:
Given data:
Abundance of C¹² = 98.89%
Abundance of C¹³ = 1.11%
Atomic mass of C¹² = 12.000 amu
Atomic mass of C¹³ = 13.003 amu
Average atomic mass = ?
Solution:
Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100
Average atomic mass of carbon= 1186.68 + 14.43333 / 100
Average atomic mass of carbon = 1201.11333 / 100
Average atomic mass of carbon = 12.01 amu.
I’m pretty sure it’s gravity man
