Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
so
1) subtract 2y in both sides: (7y-2y)-6=(2y-2y)+8 which is 5y-6=8
2) Add 6 to both sides: 5y(-6+6)=8+6 which is 5y=14
3) Divide 5 on both sides: 5y/5=14/5 which is y=14/5 or y=2.8 or y=2 4/5
Answer:
∠ I = 39°, ∠ J = 51°, ∠ K = 90°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Sum the3 angles and equate to 180
3x + 21 + 5x + 21 + 90 = 180, that is
8x + 132 = 180 ( subtract 132 from both sides )
8x = 48 ( divide both sides by 8 )
x = 6
Then
∠ I = 3x + 21 = 3(6) + 21 = 18 + 21 = 39°
∠ J = 5x + 21 = 5(6) + 21 = 30 + 21 = 51°
∠ K = 90°
Answer: M= slope
M= -3
Step-by-step explanation:
M= the change in y over the change in x so you do -4-2 over 8-6 which would give you -6 over 2 which is simplified to give you the answer which is -3
