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3 years ago

14

If you have a 59% in your class, and you take a test that is worth 200 points and it is 25% of your grade, and you get all 200 p

oints, what does that bring your grade up to?

2 answers:

valkas [14]3 years ago

6 0

Answer:

84 percent I think

Step-by-step explanation:

Leokris [45]3 years ago

4 0

Answer:

74%

Step-by-step explanation:

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Find the perimeter of WXYZ. Calculate and round each square root to the nearest tenth.

Masja [62]

Answer:

A

Step-by-step explanation:

20.7

3 0

3 years ago

Read 2 more answers

Determine if the given ordered pair is a solution to the equation. Show work full.

sleet_krkn [62]

Answer:

The ordered pair is not a solution of the equation

Step-by-step explanation:

we know that

If a ordered pair is a solution of a linear equation, then the ordered pair must satisfy the linear equation

we have

$y=-3x-13$

Substitute the value of x and the value of y of the given ordered pair in the linear equation and analyze the results

For x=-1, y=15

$15=-3(-1)-13$

$15=3-13$

$15=-10$ ----> is not true

so

the ordered pair not satisfy the equation

therefore

The ordered pair is not a solution of the equation

5 0

3 years ago

PLEASE HELP! DUE AT 11:59 PST

Nesterboy [21]

Answer:

Y = 15x + 30 and 8 hours

Step-by-step explanation:

She gets $15 per hour so her income is based on her hours, but we don't know what that is yet so, 15x.

She gets a solid $30 every week that is straight forward

To solve the function

150 = 15x + 30

subtract 30 from both sides

120 = 15x

divide 15 from both sides

8 = x

or

x = 8

You got this :)

3 0

3 years ago

Can someone help me

erik [133]

Answer:

6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

(2x -12)/2 = arcsin(16/22×sin(24°))

x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

2x -12 = 0

x -6 = 0 . . . . . divide by 2

x = 6 . . . . . . . add 6

Then the range of values of x will be ...

6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

22² = AB² + AC² -2·AB·AC·cos(48°)

16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

22² = 2·AB²·(1-cos(48°))

16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0

3 years ago

Read 2 more answers

Explain why it's possible to draw more than two different rectangles with an area of 36 square units but if not possible draw mo

gavmur [86]

The area of a rectangle is the result of multiplying its length times its width. So the rectangles length and width are factor pairs of the area.

The number 36 has four non-equal, whole number factor pairs: (1,36) ; (2,18) ; (3,13) ; (4,9)

*note : (6,6) makes a square not rectangle

The number 15 has only two whole number factor pairs (1,15) and (3,5)

8 0

3 years ago