Answer:
1)- Variable utilities cost per machine hour = 1.6 per machine hour
2)- Fixed cost = 1740
3)-Total cost on 1220 Machine hour will be
= 3692
Step-by-step explanation:
1) CALCULATE VARIABLE UTILITIES COST PER MACHINE HOUR :
Variable utilities cost per machine hour = Change in cost/high machine hour-low machine hour
=4076-3388/1460-1030
Variable utilities cost per machine hour = 1.6 per machine hour
2) Fixed cost = Total cost-variable cost
= 3388-(1030*1.6)
Fixed cost = 1740
3) Total cost on 1220 Machine hour will be (1220*1.6+1740) = 3692
Answer:
Option B - 9 hours
Step-by-step explanation:
Given : Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 36 hours. If one additional machine were used under the same operating conditions.
To find : In how many fewer hours of simultaneous operation could the production order be filled?
Solution :
Let the numbers of hours taken including additional machine i.e. 4 machines be 'x' hours.
So, 3 machines take 36 hours
and 4 machines take x hours.
Then, 

i.e. 4 machines spend 27 hours to do work.
Number of fewer hours of simultaneous operation could the production order be filled is given by,
hours
Therefore, the work could be done in 9 hours less.
So, the correct answer is B.
Answer:
7(m + 2)
Step-by-step explanation:
1) <em>Add the numbers</em>
- 3 + 2m-1 + 5m + 12
- 14 + 2m + 5m
2)<em> Combine like terms</em>
3) <em>Rearrange terms</em>
4) <em>Common factor</em>
<em />
- <em>Factor by grouping</em>
- 3 + 2m - 1+ 5m + 12
- 7m + 14
- <em>Factor by grouping</em>
⇒ 3 + 2m - 1 + 5m + 12
⇒ 7(m + 2)
Solution: