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wlad13 [49]
3 years ago
8

Find the mean and median of data below 64,91,68,78,75,53,70,12,74

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0

Answer:

The mean is 65 and the median is 70.

Step-by-step explanation:

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Someone help me with this please ASAP thank you
Blizzard [7]

Answer: B. 20

Step-by-step explanation: 1/5 of 25 is 5 and 5 of those are red so 25-5=20

6 0
3 years ago
Read 2 more answers
A 10-ft vertical post casts a 14-inch shadow at the same time a nearby cell phone tower cast a 119-ft shadow. How tall is the ce
Yakvenalex [24]

Answer:

The cellphone towers height is 1020 ft.

Step-by-step explanation:

This question is solved using proportions, by a rule of three.

A 10-ft post casts a 14-inch shadow.

Each feet has 12 inches, which means that a post with 10 feet will cast a 14/12 = 1.167 ft shadow. How tall is the cell-phone tower with a 119-feet shadow?

10 feet post - 1.167 ft shadow

x feet tower - 119 feet shadow

Applying cross multiplication:

1.167x = 10*119

x = \frac{1190}{1.167}

x = 1020

The cellphone towers height is 1020 ft.

8 0
3 years ago
There are 49 dogs signed up for a dog show. There are 36 more small dogs than the large dogs. How many small dogs have signed up
mixer [17]

Answer:

I think it is 41.5...

3 0
3 years ago
X+2y=8<br>2x-y=1<br>mathe question​
Ira Lisetskai [31]

Answer:

x = 2 and y = 3

Step-by-step explanation:

We have

x+2y = 8 -----equation (i)

2x-y = 1 -----equation (ii)

Now,

x+2y = 8

or, x = 8-2y ------equation (iii)

Again,

2x-y = 1

or, 2x = 1+y

or, 2x-1 = y

Putting the value of 'x' from equation (iii)

or, 2(8-2y)-1 = y

or, 16-4y-1 = y

or, 16-1 = y+4y

or, 15 = 5y

or, y = 15/5

or, y = 3

Putting the value of 'y' in equation (iii)

x = 8-2y

or, x = 8-(2×3)

or, x = 8-6

or, x = 2

Therefore, x = 2 and y = 3.

4 0
3 years ago
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