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sergejj [24]
2 years ago
8

X+2y=82x-y=1mathe question​

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
4 0

Answer:

x = 2 and y = 3

Step-by-step explanation:

We have

x+2y = 8 -----equation (i)

2x-y = 1 -----equation (ii)

Now,

x+2y = 8

or, x = 8-2y ------equation (iii)

Again,

2x-y = 1

or, 2x = 1+y

or, 2x-1 = y

Putting the value of 'x' from equation (iii)

or, 2(8-2y)-1 = y

or, 16-4y-1 = y

or, 16-1 = y+4y

or, 15 = 5y

or, y = 15/5

or, y = 3

Putting the value of 'y' in equation (iii)

x = 8-2y

or, x = 8-(2×3)

or, x = 8-6

or, x = 2

Therefore, x = 2 and y = 3.

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10x + .0085x = 280000
GaryK [48]

Answer:

x = 27976.22021

Step-by-step explanation:

10x + .0085x = 280000

Combine like terms

10.0085x = 280000

Divide by 10.0085 on each side

10.0085x /10.0085= 280000/10.0085

x = 27976.22021

6 0
3 years ago
Which statement describes the translation from the graph y=|x| to the graph y=|x+3|-4?
Pavel [41]

Answer:

B) shift 3 units left and 4 units down

8 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
3 years ago
In 1999. Sara and her brother Xzavier got money when their rich uncle died. They
Hunter-Best [27]

Answer:

$406,300

Step-by-step explanation:

$2,700 + $3,600 = $6,300

$400,000 + $6,300 = $406,300

3 0
3 years ago
Describe, in general, the steps for producing a frieze pattern.
Delvig [45]

An infinite strip with a symmetric pattern is called a frieze pattern.

There are only seven possible frieze pattern.

1. Translation symmetry only.

2. Glide reflection plus translation symmetry.

3. Reflection over a horizontal line plus translation.

4. Reflection over a vertical line plus translation.

5. Rotation (a half-turn about a point on the mid line of the strip) plus translation.

6. Reflection over a vertical line plus a reflection over a horizontal line plus translation.

7. Reflection over a vertical line plus glide reflection plus translation.


6 0
3 years ago
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