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sergejj [24]
3 years ago
8

X+2y=82x-y=1mathe question​

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

x = 2 and y = 3

Step-by-step explanation:

We have

x+2y = 8 -----equation (i)

2x-y = 1 -----equation (ii)

Now,

x+2y = 8

or, x = 8-2y ------equation (iii)

Again,

2x-y = 1

or, 2x = 1+y

or, 2x-1 = y

Putting the value of 'x' from equation (iii)

or, 2(8-2y)-1 = y

or, 16-4y-1 = y

or, 16-1 = y+4y

or, 15 = 5y

or, y = 15/5

or, y = 3

Putting the value of 'y' in equation (iii)

x = 8-2y

or, x = 8-(2×3)

or, x = 8-6

or, x = 2

Therefore, x = 2 and y = 3.

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One factor of One factor of f(x)=5x^3+5x^2-170x + 280 is (x +
SpyIntel [72]

Answer:

x = –7, x = 2, or x = 4 are factors of f(x).

Step-by-step explanation:

Given : f(x)  = 5x³ +5x²-170x +280 and x + 7 is one factor .

To find  : What are all the roots of the function.

Solution :  f(x)  = 5x³ +5x²-170x +280 .

We have given that x + 7 is factor that mean x = -7 is factor of f(x )

When we divide f(x) by x +7 we get

5x² -30x +40 =0

Taking common 5 from equation

5( x² -6x +8) =0

On dividing by 5 both sides

x² -6x +8 = 0

On factoring

x² -2x -4x +8 = 0.

Taking common x from first two terms and -4 from last two terms

x ( x -2) -4 (x -2) = 0

On grouping

(x-2) (x-4) = 0

x -2 =0

x =2

x-4 =0

x = 4

Therefore, x = –7, x = 2, or x = 4 are factors of f(x).

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